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Sequences and Series: Arithmetic, Geometric, and Beyond

2026.04.14

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Sequences and series
Sequences and series

A sequence is an ordered list of numbers following a pattern. A series is what you get when you add them up. These concepts are fundamental to calculus and appear across standardized tests.

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Key Point: Sequences and series appear on AP Calculus BC (convergence tests), A-levels, and college entrance exams. Arithmetic and geometric types cover 90% of exam questions.

Arithmetic Sequences

Each term increases by a constant difference dd.

an=a1+(nβˆ’1)da_n = a_1 + (n-1)d
  • a1a_1 : first term
  • dd : common difference
  • ana_n : nth term

Example: 2,5,8,11,…2, 5, 8, 11, \ldots has a1=2a_1 = 2, d=3d = 3.

Sum of an Arithmetic Series

Sn=n2(a1+an)=n2{2a1+(nβˆ’1)d}S_n = \frac{n}{2}(a_1 + a_n) = \frac{n}{2}\{2a_1 + (n-1)d\}

Geometric Sequences

Each term is multiplied by a constant ratio rr.

an=a1β‹…rnβˆ’1a_n = a_1 \cdot r^{n-1}
  • a1a_1 : first term
  • rr : common ratio
  • ana_n : nth term

Example: 3,6,12,24,…3, 6, 12, 24, \ldots has a1=3a_1 = 3, r=2r = 2.

Sum of a Geometric Series

Finite (r≠1r \neq 1):

Sn=a1β‹…1βˆ’rn1βˆ’rS_n = a_1 \cdot \frac{1 - r^n}{1 - r}

Infinite (∣r∣<1|r| < 1):

S∞=a11βˆ’rS_{\infty} = \frac{a_1}{1 - r}
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Watch Out: The infinite sum formula only works when ∣r∣<1|r| < 1. If ∣r∣β‰₯1|r| \geq 1, the series diverges and has no finite sum.

Comparison Table

PropertyArithmeticGeometric
PatternAdd ddMultiply by rr
nth terma1+(nβˆ’1)da_1 + (n-1)da1β‹…rnβˆ’1a_1 \cdot r^{n-1}
Finite sumn2(a1+an)\frac{n}{2}(a_1 + a_n)a1β‹…1βˆ’rn1βˆ’ra_1 \cdot \frac{1-r^n}{1-r}
Infinite sumDiverges (always)a11βˆ’r\frac{a_1}{1-r} if ∣r∣<1|r| < 1

How to Identify the Type

  1. Check the differences: Subtract consecutive terms. If they’re constant β†’ Arithmetic.
  2. Check the ratios: Divide consecutive terms. If they’re constant β†’ Geometric.
  3. Neither constant? β†’ It might be a different type (quadratic, recursive, etc.).

Worked Examples

Example 1: Arithmetic β€” Find the 20th Term

For the sequence 5,9,13,17,…5, 9, 13, 17, \ldots, find a20a_{20}.

Show Solution

a1=5a_1 = 5, d=4d = 4

a20=5+(20βˆ’1)(4)=5+76=81a_{20} = 5 + (20-1)(4) = 5 + 76 = 81

Example 2: Geometric β€” Sum of First 6 Terms

For a1=2a_1 = 2, r=3r = 3, find S6S_6.

Show Solution
S6=2β‹…1βˆ’361βˆ’3=2β‹…1βˆ’729βˆ’2=728S_6 = 2 \cdot \frac{1 - 3^6}{1 - 3} = 2 \cdot \frac{1 - 729}{-2} = 728

Example 3: Infinite Geometric Series

Find the sum of 8+4+2+1+…8 + 4 + 2 + 1 + \ldots

Show Solution

a1=8a_1 = 8, r=12r = \frac{1}{2}. Since ∣r∣<1|r| < 1:

S∞=81βˆ’12=16S_{\infty} = \frac{8}{1 - \frac{1}{2}} = 16
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Pro Tip: When given a series problem, always identify whether it’s arithmetic or geometric first. This determines which formula to use. Check differences, then ratios.

Top 3 Common Mistakes

  1. Off-by-one error in the nth term β€” it’s (nβˆ’1)d(n-1)d, not ndnd, because the first term has zero differences added
  2. Using the infinite sum when ∣r∣β‰₯1|r| \geq 1 β€” the series diverges, so there’s no finite answer
  3. Confusing ana_n with SnS_n β€” ana_n is a single term, SnS_n is the sum of the first nn terms

Related Topics

  • Sigma Notation and Summation
  • Convergence Tests (AP Calc BC)
  • Recursive Sequences
  • Mathematical Induction