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Logarithm Essentials: Definition, Properties, and Calculations

2026.04.24

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Math study
Math study

Logarithms are the inverse of exponentiation and one of the most frequently tested concepts in high school math. They go hand-in-hand with exponential functions and appear throughout algebra and calculus.

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Logarithms appear in 2–3 questions on most standardized math exams. Master the definition and the three key laws, and you can solve the vast majority of log problems.

What Is a Logarithm?

Definition

A logarithm answers the question: "How many times must I multiply the base to get this number?"

For a>0a > 0, a1a \neq 1, and N>0N > 0, if ax=Na^x = N then x=logaNx = \log_a N.

logaN=x    ax=N\log_a N = x \iff a^x = N

Here aa is the base and NN is the argument.

Conditions for a Valid Logarithm

A logarithm logaN\log_a N is defined only when:

  1. Base condition: a>0a > 0 and a1a \neq 1
  2. Argument condition: N>0N > 0
  3. If either condition fails, the logarithm is undefined

Common Log vs Natural Log

TypeBaseNotationUse
Common log10logN\log N (base omitted)Digit counting, standardized tests
Natural loge2.718e \approx 2.718lnN\ln NCalculus, science

Logarithm Properties and Laws

Step 1: Basic Properties

For any valid base aa:

loga1=0(a0=1)\log_a 1 = 0 \quad (\because a^0 = 1)

logaa=1(a1=a)\log_a a = 1 \quad (\because a^1 = a)

alogaN=Na^{\log_a N} = N

Step 2: The Three Laws of Logarithms

For M>0M > 0 and N>0N > 0:

Law 1 — Product → Addition

logaMN=logaM+logaN\log_a MN = \log_a M + \log_a N

Law 2 — Quotient → Subtraction

logaMN=logaMlogaN\log_a \frac{M}{N} = \log_a M - \log_a N

Law 3 — Power → Multiplication

logaMk=klogaM\log_a M^k = k \log_a M

Step 3: Change of Base Formula

The key formula for converting between different bases:

logab=logcblogca\log_a b = \frac{\log_c b}{\log_c a}

Useful variations:

logab=1logba\log_a b = \frac{1}{\log_b a}

logablogbc=logac\log_a b \cdot \log_b c = \log_a c

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The most common mistake is thinking loga(M+N)=logaM+logaN\log_a(M + N) = \log_a M + \log_a N. The product rule only works for multiplication inside the log, not addition!

Advanced: Applications of Logarithms

Finding the Number of Digits

The number of digits in a positive integer NN is log10N+1\lfloor \log_{10} N \rfloor + 1.

For example, 210=10242^{10} = 1024:

log1010243.013.01+1=4 digits\log_{10} 1024 \approx 3.01 \Rightarrow \lfloor 3.01 \rfloor + 1 = 4 \text{ digits}


Practice Problems

Example 1: Applying Log Laws

Problem: Find the value of log212log23\log_2 12 - \log_2 3.

Show Solution

Apply the quotient rule:

log212log23=log2123=log24=2\log_2 12 - \log_2 3 = \log_2 \frac{12}{3} = \log_2 4 = 2

Answer: 22

Example 2: Change of Base

Problem: Find the value of log23×log38\log_2 3 \times \log_3 8.

Show Solution

Use the chain rule for logarithms:

log23×log38=log28=3\log_2 3 \times \log_3 8 = \log_2 8 = 3

Alternatively, log38=3log32\log_3 8 = 3\log_3 2, so:

log23×3log32=3×log23×1log23=3\log_2 3 \times 3\log_3 2 = 3 \times \log_2 3 \times \frac{1}{\log_2 3} = 3

Answer: 33

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When solving log problems, always start by unifying the bases and prime-factoring the arguments. Most problems are solved in these two steps.

Top 3 Common Mistakes

  1. Ignoring the argument condition — Forgetting to check N>0N > 0 in logaN\log_a N and substituting negative numbers or zero. Always verify the argument after solving.
  2. Confusing addition with multiplicationlog(M+N)logM+logN\log(M + N) \neq \log M + \log N. You can only separate logs when the argument is a product.
  3. Swapping numerator and denominator in base change — In logab=logbloga\log_a b = \frac{\log b}{\log a}, bb is in the numerator and aa is in the denominator.

Related Concepts

  • Exponential Functions — inverse pair
  • Integration — log in calculus
  • Quadratic Equations — algebraic foundation