Logarithm Essentials: Definition, Properties, and Calculations
2026.04.24
Learn.byAuthor
Math study
Logarithms are the inverse of exponentiation and one of the most frequently tested concepts in high school math. They go hand-in-hand with exponential functions and appear throughout algebra and calculus.
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Logarithms appear in 2–3 questions on most standardized math exams. Master the definition and the three key laws, and you can solve the vast majority of log problems.
What Is a Logarithm?
Definition
A logarithm answers the question: "How many times must I multiply the base to get this number?"
For a>0, a=1, and N>0, if ax=N then x=logaN.
logaN=x⟺ax=N
Here a is the base and N is the argument.
Conditions for a Valid Logarithm
A logarithm logaN is defined only when:
Base condition: a>0 and a=1
Argument condition: N>0
If either condition fails, the logarithm is undefined
Common Log vs Natural Log
Type
Base
Notation
Use
Common log
10
logN (base omitted)
Digit counting, standardized tests
Natural log
e≈2.718
lnN
Calculus, science
Logarithm Properties and Laws
Step 1: Basic Properties
For any valid base a:
loga1=0(∵a0=1)
logaa=1(∵a1=a)
alogaN=N
Step 2: The Three Laws of Logarithms
For M>0 and N>0:
Law 1 — Product → Addition
logaMN=logaM+logaN
Law 2 — Quotient → Subtraction
logaNM=logaM−logaN
Law 3 — Power → Multiplication
logaMk=klogaM
Step 3: Change of Base Formula
The key formula for converting between different bases:
logab=logcalogcb
Useful variations:
logab=logba1
logab⋅logbc=logac
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The most common mistake is thinking loga(M+N)=logaM+logaN. The product rule only works for multiplication inside the log, not addition!
Advanced: Applications of Logarithms
Finding the Number of Digits
The number of digits in a positive integer N is ⌊log10N⌋+1.
For example, 210=1024:
log101024≈3.01⇒⌊3.01⌋+1=4 digits
Practice Problems
Example 1: Applying Log Laws
Problem: Find the value of log212−log23.
Show Solution
Apply the quotient rule:
log212−log23=log2312=log24=2
Answer: 2
Example 2: Change of Base
Problem: Find the value of log23×log38.
Show Solution
Use the chain rule for logarithms:
log23×log38=log28=3
Alternatively, log38=3log32, so:
log23×3log32=3×log23×log231=3
Answer: 3
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When solving log problems, always start by unifying the bases and prime-factoring the arguments. Most problems are solved in these two steps.
Top 3 Common Mistakes
Ignoring the argument condition — Forgetting to check N>0 in logaN and substituting negative numbers or zero. Always verify the argument after solving.
Confusing addition with multiplication — log(M+N)=logM+logN. You can only separate logs when the argument is a product.
Swapping numerator and denominator in base change — In logab=logalogb, b is in the numerator and a is in the denominator.