Símbolos
Problema
a) $\right)$ $\dfrac {7} {12}+\dfrac {1} {4}-\dfrac {3} {θ}=$ b) $\dfrac {12} {5}-\dfrac {3} {4}+2=$ $c\right)\dfrac {10} {3}+\dfrac {2} {7}.\dfrac {1} {2}=$ d) $\dfrac {4} {9}+\dfrac {6} {18}-\dfrac {5} {3}=$ $\right)$ $\dfrac {1} {2}+\dfrac {3} {4}+\dfrac {1} {6}=$ $0$ $2^{%}$ $3\dfrac {2} {3}-4\dfrac {1} {2}=$ $9\right)$ $3\dfrac {1} {4}$ $-\dfrac {3} {2}+1\dfrac {1} {5}$ $2°$
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Solución
Profesor de Qanda - DiegoJPP