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$\left(\dfrac {2} {5}x^{3}+\dfrac {4} {6}x^{2}-5\right)+\left(\dfrac {1} {10}x^{3}-\dfrac {1} {3}x^{2}+8\right)=$ $b\right)$ $\left(\dfrac {7} {3}x^{3}+\dfrac {2} {5}x^{2}-\dfrac {3} {8}\right)+\left(\dfrac {3} {5}x^{5}+4\right)=$
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Aritmética y álgebra
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Solución
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Profesor de Qanda - dany
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