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Problema
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$\left(-4\right)\left(+10\right)=c$ $\left(+9\left(-7.8\right)=$ $\left(-5\right)\left(-3\right)=+1^{5}$ $△\left(-8\right)\left(+3\right)\left(-5\right)=$ $\left(+7\right)\left(+8\right)==$ $\left(-0.7\right)\left(+2.3\right)=$ $\left(+12\right)\left(-4\right)=-48$ ( $\left(-9\right)=-54$ $\left(-6\right)\left(-$ $\right)=+54$ ) $1\left(-3.7\right)=$ $\left(-\pi .8\left(-1.1\right)=$ $\left(+6\right)\left(-2\right)\left(-4\right)\left(+1\right)=$ $\left(-5.5\right)$ ( = 0 $\left(+7\right)\left(-3\right)\left(-0.3\right)\left(+\right)=$ $\left(\dfrac {3} {5}\left(\dfrac {5} {6}\right)=$ $\left(\dfrac {7} {8}\right)-\dfrac {1} {3}\right)=$ $\left(+\dfrac {1} {2}\right)\dfrac {1} {3}\left(-\dfrac {2} {5}\right)=$
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Solución
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Profesor de Qanda - Milagros25
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