qanda-logo
search-icon
Símbolos
Problema
solution-image
$4$ $\dfrac {15} {20}=\dfrac {21} {x}$ $\dfrac {x} {24}<\dfrac {40} {66}$ $\dfrac {x} {72}<\dfrac {5y} {212}$ FRANCIA $44$ MEXICO $\pi 0$ ESPAÑA $01$ $4$ $\dfrac {14} {35}=\dfrac {284} {x}$ $\dfrac {7} {25}.\dfrac {x} {25}$ $\dfrac {21} {6}=\dfrac {x} {24}$ ALEMANIA $74$ ARGENTINA $\pi 1$ ITALIA S0 $\dfrac {28} {x}$ $\dfrac {35} {45}$ $\dfrac {17} {x}=\dfrac {68} {372}$ $\dfrac {24} {18}=\dfrac {x} {54}$
Secundaria
Geometría
Búsquedas: 105
Solución
answer-user-profile-image
Profesor de Qanda - LuceroRT
answer-reply-image
Si tienes alguna duda no dudes en hacérmela saber c: