# Calculator search results

Formula
$$x ^ { 2 } + 2 x + 3 = 0$$
 Do not have the solution 
$x = \dfrac { - 2 \pm \sqrt{ \color{#FF6800}{ 2 } ^ { \color{#FF6800}{ 2 } } - 4 \times 1 \times 3 } } { 2 \times 1 }$
 Calculate power 
$x = \dfrac { - 2 \pm \sqrt{ \color{#FF6800}{ 4 } - 4 \times 1 \times 3 } } { 2 \times 1 }$
$x = \dfrac { - 2 \pm \sqrt{ 4 - 4 \color{#FF6800}{ \times } \color{#FF6800}{ 1 } \times 3 } } { 2 \times 1 }$
 Multiplying any number by 1 does not change the value 
$x = \dfrac { - 2 \pm \sqrt{ 4 - 4 \times 3 } } { 2 \times 1 }$
$x = \dfrac { - 2 \pm \sqrt{ 4 \color{#FF6800}{ - } \color{#FF6800}{ 4 } \color{#FF6800}{ \times } \color{#FF6800}{ 3 } } } { 2 \times 1 }$
 Multiply $- 4$ and $3$
$x = \dfrac { - 2 \pm \sqrt{ 4 \color{#FF6800}{ - } \color{#FF6800}{ 12 } } } { 2 \times 1 }$
$x = \dfrac { - 2 \pm \sqrt{ \color{#FF6800}{ 4 } \color{#FF6800}{ - } \color{#FF6800}{ 12 } } } { 2 \times 1 }$
 Subtract $12$ from $4$
$x = \dfrac { - 2 \pm \sqrt{ \color{#FF6800}{ - } \color{#FF6800}{ 8 } } } { 2 \times 1 }$
$x = \dfrac { - 2 \pm \sqrt{ - 8 } } { 2 \color{#FF6800}{ \times } \color{#FF6800}{ 1 } }$
 Multiplying any number by 1 does not change the value 
$x = \dfrac { - 2 \pm \sqrt{ - 8 } } { \color{#FF6800}{ 2 } }$
$\color{#FF6800}{ x } = \color{#FF6800}{ \dfrac { - 2 \pm \sqrt{ - 8 } } { 2 } }$
 The square root of a negative number does not exist within the set of real numbers 
 Do not have the solution 
Try more features at Qanda!
Search by problem image
Ask 1:1 question to TOP class teachers
AI recommend problems and video lecture