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Formula
$$x ^ { 2 } + 7 x + 6 = 0$$
$\begin{array} {l} x = - 1 \\ x = - 6 \end{array}$
$\color{#FF6800}{ x } = \color{#FF6800}{ \dfrac { - 7 \pm \sqrt{ 7 ^ { 2 } - 4 \times 1 \times 6 } } { 2 \times 1 } }$
 Organize the expression 
$\color{#FF6800}{ x } = \color{#FF6800}{ \dfrac { - 7 \pm \sqrt{ 25 } } { 2 \times 1 } }$
$x = \dfrac { - 7 \pm \sqrt{ \color{#FF6800}{ 25 } } } { 2 \times 1 }$
 Organize the part that can be taken out of the radical sign inside the square root symbol 
$x = \dfrac { - 7 \pm \color{#FF6800}{ 5 } } { 2 \times 1 }$
$x = \dfrac { - 7 \pm 5 } { 2 \color{#FF6800}{ \times } \color{#FF6800}{ 1 } }$
 Multiplying any number by 1 does not change the value 
$x = \dfrac { - 7 \pm 5 } { \color{#FF6800}{ 2 } }$
$\color{#FF6800}{ x } = \color{#FF6800}{ \dfrac { - 7 \pm 5 } { 2 } }$
 Separate the answer 
$\begin{array} {l} \color{#FF6800}{ x } = \color{#FF6800}{ \dfrac { - 7 + 5 } { 2 } } \\ \color{#FF6800}{ x } = \color{#FF6800}{ \dfrac { - 7 - 5 } { 2 } } \end{array}$
$\begin{array} {l} x = \dfrac { \color{#FF6800}{ - } \color{#FF6800}{ 7 } \color{#FF6800}{ + } \color{#FF6800}{ 5 } } { 2 } \\ x = \dfrac { - 7 - 5 } { 2 } \end{array}$
 Add $- 7$ and $5$
$\begin{array} {l} x = \dfrac { \color{#FF6800}{ - } \color{#FF6800}{ 2 } } { 2 } \\ x = \dfrac { - 7 - 5 } { 2 } \end{array}$
$\begin{array} {l} x = \color{#FF6800}{ \dfrac { - 2 } { 2 } } \\ x = \dfrac { - 7 - 5 } { 2 } \end{array}$
 Do the reduction of the fraction format 
$\begin{array} {l} x = \color{#FF6800}{ \dfrac { - 1 } { 1 } } \\ x = \dfrac { - 7 - 5 } { 2 } \end{array}$
$\begin{array} {l} x = \dfrac { - 1 } { \color{#FF6800}{ 1 } } \\ x = \dfrac { - 7 - 5 } { 2 } \end{array}$
 If the denominator is 1, the denominator can be removed 
$\begin{array} {l} x = \color{#FF6800}{ - } \color{#FF6800}{ 1 } \\ x = \dfrac { - 7 - 5 } { 2 } \end{array}$
$\begin{array} {l} x = - 1 \\ x = \dfrac { \color{#FF6800}{ - } \color{#FF6800}{ 7 } \color{#FF6800}{ - } \color{#FF6800}{ 5 } } { 2 } \end{array}$
 Find the sum of the negative numbers 
$\begin{array} {l} x = - 1 \\ x = \dfrac { \color{#FF6800}{ - } \color{#FF6800}{ 12 } } { 2 } \end{array}$
$\begin{array} {l} x = - 1 \\ x = \color{#FF6800}{ \dfrac { - 12 } { 2 } } \end{array}$
 Do the reduction of the fraction format 
$\begin{array} {l} x = - 1 \\ x = \color{#FF6800}{ \dfrac { - 6 } { 1 } } \end{array}$
$\begin{array} {l} x = - 1 \\ x = \dfrac { - 6 } { \color{#FF6800}{ 1 } } \end{array}$
 If the denominator is 1, the denominator can be removed 
$\begin{array} {l} x = - 1 \\ x = \color{#FF6800}{ - } \color{#FF6800}{ 6 } \end{array}$
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