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Formula
Solve the quadratic equation
Answer
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$$4 x ^ { 2 } - 12 x + 9 = 0$$
$x = \dfrac { 3 } { 2 }$
Calculate using the quadratic formula
$x = \dfrac { \color{#FF6800}{ - } \left ( \color{#FF6800}{ - } 12 \right ) \pm \sqrt{ \left ( - 12 \right ) ^ { 2 } - 4 \times 4 \times 9 } } { 2 \times 4 }$
$ $ Simplify Minus $ $
$x = \dfrac { 12 \pm \sqrt{ \left ( - 12 \right ) ^ { 2 } - 4 \times 4 \times 9 } } { 2 \times 4 }$
$x = \dfrac { 12 \pm \sqrt{ \left ( \color{#FF6800}{ - } \color{#FF6800}{ 12 } \right ) ^ { \color{#FF6800}{ 2 } } - 4 \times 4 \times 9 } } { 2 \times 4 }$
$ $ Remove negative signs because negative numbers raised to even powers are positive $ $
$x = \dfrac { 12 \pm \sqrt{ 12 ^ { 2 } - 4 \times 4 \times 9 } } { 2 \times 4 }$
$x = \dfrac { 12 \pm \sqrt{ \color{#FF6800}{ 12 } ^ { \color{#FF6800}{ 2 } } - 4 \times 4 \times 9 } } { 2 \times 4 }$
$ $ Calculate power $ $
$x = \dfrac { 12 \pm \sqrt{ \color{#FF6800}{ 144 } - 4 \times 4 \times 9 } } { 2 \times 4 }$
$x = \dfrac { 12 \pm \sqrt{ 144 \color{#FF6800}{ - } \color{#FF6800}{ 4 } \color{#FF6800}{ \times } \color{#FF6800}{ 4 } \color{#FF6800}{ \times } \color{#FF6800}{ 9 } } } { 2 \times 4 }$
$ $ Multiply the numbers $ $
$x = \dfrac { 12 \pm \sqrt{ 144 \color{#FF6800}{ - } \color{#FF6800}{ 144 } } } { 2 \times 4 }$
$x = \dfrac { 12 \pm \sqrt{ \color{#FF6800}{ 144 } \color{#FF6800}{ - } \color{#FF6800}{ 144 } } } { 2 \times 4 }$
$ $ Remove the two numbers if the values are the same and the signs are different $ $
$x = \dfrac { 12 \pm \sqrt{ 0 } } { 2 \times 4 }$
$x = \dfrac { 12 \pm \sqrt{ \color{#FF6800}{ 0 } } } { 2 \times 4 }$
$n square root $ of 0 is 0 $ $
$x = \dfrac { 12 \pm \color{#FF6800}{ 0 } } { 2 \times 4 }$
$x = \dfrac { 12 \pm 0 } { \color{#FF6800}{ 2 } \color{#FF6800}{ \times } \color{#FF6800}{ 4 } }$
$ $ Multiply $ 2 $ and $ 4$
$x = \dfrac { 12 \pm 0 } { \color{#FF6800}{ 8 } }$
$\color{#FF6800}{ x } = \color{#FF6800}{ \dfrac { 12 \pm 0 } { 8 } }$
$ $ The value will not be changed even if adding or subtracting 0 $ $
$\color{#FF6800}{ x } = \color{#FF6800}{ \dfrac { 12 } { 8 } }$
$x = \color{#FF6800}{ \dfrac { 12 } { 8 } }$
$ $ Do the reduction of the fraction format $ $
$x = \color{#FF6800}{ \dfrac { 3 } { 2 } }$
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