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Formula
Calculate the value
Answer
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$$\sqrt{ 2 + \sqrt{ 3 } }$$
$\dfrac { \sqrt{ 2 } + \sqrt{ 6 } } { 2 }$
Calculate the value
$\sqrt{ \color{#FF6800}{ 2 } \color{#FF6800}{ + } \sqrt{ \color{#FF6800}{ 3 } } }$
$ $ Simplify the expression by arranging the expression in the radical sign $ $
$\color{#FF6800}{ \dfrac { \sqrt{ \color{#FF6800}{ 2 } } } { \color{#FF6800}{ 2 } } } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { \sqrt{ \color{#FF6800}{ 6 } } } { \color{#FF6800}{ 2 } } }$
$\color{#FF6800}{ \dfrac { \sqrt{ \color{#FF6800}{ 2 } } } { \color{#FF6800}{ 2 } } } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { \sqrt{ \color{#FF6800}{ 6 } } } { \color{#FF6800}{ 2 } } }$
$ $ Combine the fraction with the same denominator $ $
$\dfrac { \sqrt{ \color{#FF6800}{ 2 } } \color{#FF6800}{ + } \sqrt{ \color{#FF6800}{ 6 } } } { 2 }$
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