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Formula
Find the sum of the fractions
Answer
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$$\dfrac { 3 } { 4 } + \dfrac { 1 } { 6 }$$
$\dfrac { 11 } { 12 }$
Find the sum of the fractions
$\dfrac { 3 } { \color{#FF6800}{ 4 } } + \dfrac { 1 } { \color{#FF6800}{ 6 } }$
$ $ The smallest common multiple in denominator is $ 12$
$\dfrac { 3 } { \color{#FF6800}{ 4 } } + \dfrac { 1 } { \color{#FF6800}{ 6 } }$
$\dfrac { 3 } { 4 } + \dfrac { 1 } { 6 }$
$ $ Multiply the denominator and the numerator so that the denominator is the smallest common multiple $ $
$\dfrac { 3 \times \color{#FF6800}{ 3 } } { 4 \times \color{#FF6800}{ 3 } } + \dfrac { 1 \times \color{#FF6800}{ 2 } } { 6 \times \color{#FF6800}{ 2 } }$
$\color{#FF6800}{ \dfrac { \color{#FF6800}{ 3 } \color{#FF6800}{ \times } \color{#FF6800}{ 3 } } { \color{#FF6800}{ 4 } \color{#FF6800}{ \times } \color{#FF6800}{ 3 } } } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { \color{#FF6800}{ 1 } \color{#FF6800}{ \times } \color{#FF6800}{ 2 } } { \color{#FF6800}{ 6 } \color{#FF6800}{ \times } \color{#FF6800}{ 2 } } }$
$ $ Organize the expression $ $
$\color{#FF6800}{ \dfrac { \color{#FF6800}{ 9 } } { \color{#FF6800}{ 12 } } } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { \color{#FF6800}{ 2 } } { \color{#FF6800}{ 12 } } }$
$\color{#FF6800}{ \dfrac { \color{#FF6800}{ 9 } } { \color{#FF6800}{ 12 } } } \color{#FF6800}{ + } \color{#FF6800}{ \dfrac { \color{#FF6800}{ 2 } } { \color{#FF6800}{ 12 } } }$
$ $ Since the denominator is the same as $ 12 $ , combine the fractions into one $ $
$\color{#FF6800}{ \dfrac { \color{#FF6800}{ 9 } \color{#FF6800}{ + } \color{#FF6800}{ 2 } } { \color{#FF6800}{ 12 } } }$
$\dfrac { \color{#FF6800}{ 9 } \color{#FF6800}{ + } \color{#FF6800}{ 2 } } { 12 }$
$ $ Add $ 9 $ and $ 2$
$\dfrac { \color{#FF6800}{ 11 } } { 12 }$
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