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$$x ^ { 2 } - 2 x + 3 = 0$$
 Do not have the solution 
$x = \dfrac { \color{#FF6800}{ - } \left ( \color{#FF6800}{ - } 2 \right ) \pm \sqrt{ \left ( - 2 \right ) ^ { 2 } - 4 \times 1 \times 3 } } { 2 \times 1 }$
 Simplify Minus 
$x = \dfrac { 2 \pm \sqrt{ \left ( - 2 \right ) ^ { 2 } - 4 \times 1 \times 3 } } { 2 \times 1 }$
$x = \dfrac { 2 \pm \sqrt{ \left ( \color{#FF6800}{ - } \color{#FF6800}{ 2 } \right ) ^ { \color{#FF6800}{ 2 } } - 4 \times 1 \times 3 } } { 2 \times 1 }$
 Remove negative signs because negative numbers raised to even powers are positive 
$x = \dfrac { 2 \pm \sqrt{ 2 ^ { 2 } - 4 \times 1 \times 3 } } { 2 \times 1 }$
$x = \dfrac { 2 \pm \sqrt{ \color{#FF6800}{ 2 } ^ { \color{#FF6800}{ 2 } } - 4 \times 1 \times 3 } } { 2 \times 1 }$
 Calculate power 
$x = \dfrac { 2 \pm \sqrt{ \color{#FF6800}{ 4 } - 4 \times 1 \times 3 } } { 2 \times 1 }$
$x = \dfrac { 2 \pm \sqrt{ 4 - 4 \color{#FF6800}{ \times } \color{#FF6800}{ 1 } \times 3 } } { 2 \times 1 }$
 Multiplying any number by 1 does not change the value 
$x = \dfrac { 2 \pm \sqrt{ 4 - 4 \times 3 } } { 2 \times 1 }$
$x = \dfrac { 2 \pm \sqrt{ 4 \color{#FF6800}{ - } \color{#FF6800}{ 4 } \color{#FF6800}{ \times } \color{#FF6800}{ 3 } } } { 2 \times 1 }$
 Multiply $- 4$ and $3$
$x = \dfrac { 2 \pm \sqrt{ 4 \color{#FF6800}{ - } \color{#FF6800}{ 12 } } } { 2 \times 1 }$
$x = \dfrac { 2 \pm \sqrt{ \color{#FF6800}{ 4 } \color{#FF6800}{ - } \color{#FF6800}{ 12 } } } { 2 \times 1 }$
 Subtract $12$ from $4$
$x = \dfrac { 2 \pm \sqrt{ \color{#FF6800}{ - } \color{#FF6800}{ 8 } } } { 2 \times 1 }$
$x = \dfrac { 2 \pm \sqrt{ - 8 } } { 2 \color{#FF6800}{ \times } \color{#FF6800}{ 1 } }$
 Multiplying any number by 1 does not change the value 
$x = \dfrac { 2 \pm \sqrt{ - 8 } } { \color{#FF6800}{ 2 } }$
$\color{#FF6800}{ x } = \color{#FF6800}{ \dfrac { 2 \pm \sqrt{ - 8 } } { 2 } }$
 The square root of a negative number does not exist within the set of real numbers 
 Do not have the solution 
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