Problem

Activity
A. Solve the following rational equations. Check for extraneous solution.
$1.$ $6$ $x--=-5$ $\dfrac {6} {x}=-5$ $3.3x=\dfrac {5x+6} {2x+3}$
$2.$ $\dfrac {6} {3x}+\dfrac {5} {4}=\dfrac {3} {x}$ $4.3$ $\dfrac {x^{2}-1} {x-3}=\dfrac {8} {x-3}$

10th-13th grade

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Solution

Qanda teacher - Meena

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$H.$ Solve the fo!lowing rational equations and check for extraneous solutions.
$6$ $\dfrac {x^{2}-1} {x-3}=\dfrac {8} {x-3}$ $7$ $\dfrac {3c} {c^{2}-4}+\dfrac {1} {c-2}=\dfrac {2} {c+2}$

10th-13th grade

Other