3. Verify whether the values of x given in each case are the zeroes of the polynomial or not?. $\left(1\right)$ ) $p\left(x\right)=2x+1:x=-\dfrac {1} {2}$ $\left(i\right)$ $p\left(x\right)=5x-\pi :x=\dfrac {-3} {2}$ Gi) $p\left(x\right)=x^{2}-1$ $x=±1$ $\left(iV\right)$ $p\left(x\right)=\left(x-1\right)\left(x+2\right)$ $x=-1$ $-2$ $\left(V\right)$ $p\left(y\right)=y^{2}:y=0$ $\left(m\right)$ $p\left(x\right)=ax+b:x=-\dfrac {b} {a}$ (vii) $f\left(x\right)=3x^{2}-1$ $x=-\dfrac {1} {\sqrt{3} },\dfrac {2} {\sqrt{3} }$ $\left(nii\right)$ $f\left(x\right)=2x-1,x=\dfrac {1} {2},\dfrac {-1} {2}$

$3.$ Verify whether the values of $X$ given in each case are the zeroes of the polynomial or not ? AS, Each $11a\right)$ $\right)$ ) $p\left(x\right)=2x+1:x=\dfrac {-1} {2}$

Verify whether the values of x given in each case are the zeroes of the polynomial or not?. $\left(0$ $P\left(x\right)=$ $P\left(x\right)=2x+1:x=-\dfrac {1} {2}$ (i $p\left(x\right)=5x-\pi 5x=\dfrac {-3} {2}$ $P\left(x\right)=x^{2}-1:x=±1$ $\left(w\right)$ $p\left(x\right)=\left(x-1\right)\left(x+2\right)$ $x=-1.$ $-1.-2$ $y\right)$ $P\left(y\right)=y^{2}:y=0$ $\left(M\right)$ $p\left(x\right)=ax+b:x=-\dfrac {b} {a}$ $4\right)$ $f\left(x\right)=3x^{2}-1$ $x=-\dfrac {1} {\sqrt{3} },\dfrac {2} {\bar{\sqrt{3} } }$ $\left(nn\right)$ $f\left(x\right)=2x-1.x=\dfrac {1} {2}$ $\dfrac {-1} {2}$