Problem

Step $2$ Muitiply.
$\dfrac {x^{2}-9} {x-3}.\dfrac {x-3} {x+3}$ $=$ $\dfrac {x^{3}-9x-3x^{2}+27} {x^{2}-6x+9}$

7th-9th grade

Algebra

Solution

Qanda teacher - Chandrabha

incomplete questions

Still don't get it?

Ask this question to Qanda teacherSimilar problem