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Step $2$ Muitiply. $\dfrac {x^{2}-9} {x-3}.\dfrac {x-3} {x+3}$ $=$ $\dfrac {x^{3}-9x-3x^{2}+27} {x^{2}-6x+9}$
7th-9th grade
Algebra
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Qanda teacher - Chandrabha
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