Problem

Solve each equation and check the solution.
$1.$ $\dfrac {x} {9}-\dfrac {2} {5}=$
$\dfrac {x} {9}-\dfrac {2} {5}=\dfrac {1} {3}$
$\dfrac {x} {5}=15+\dfrac {x} {3}$
$2.$ $\dfrac {x} {5}=$
$3.$ $\dfrac {3} {x}=\dfrac {4} {3x}-\dfrac {10} {3}$ $.$ $IOP|C:$ $.$ Solving Rational
Equation and Inequalities
$4.$ $\dfrac {7} {x}+\dfrac {1} {4}=\dfrac {9} {x}$
ebia
$5.$ $\dfrac {x} {6}+\dfrac {3x} {5}=2$

10th-13th grade

Other

Search count: 111

Solution

Qanda teacher - priya

Student

that's the answer key teacher

thank you ma'am

Qanda teacher - priya

Student

thank very much

Qanda teacher - priya

please evaluate

Still don't get it?

Ask this question to Qanda teacherSimilar problem

Which of the following rational numbers are
equivalent?
$0Ptionsy$
A \frac{5}{6}, \frac{30}{36}
B $s\sqrt{rac\left(} -2\right)\left(3\right)\sqrt{1rac} \sqrt{4\right)16\right)4} $
C $s\sqrt{11aC\left(} -4\right)1-7b,\sqrt{1rac\left(16\sqrt{35\right)9} } $
D \frac{1}{2},\frac{3}{8}

7th-9th grade

Other

Search count: 5,909