Problem

In a trangle, suppose that the length of a side p is two mches longer than side g. The
length of side gis three times 25 long as side $+8\pi D505z$ that the perimeter of the triangle
$15$ $3=$ mches. Find the length of each side.
$\left(z$ $-$ $17=$ $25$ $2=5=$
(b) $18=2\pi $ $155\pi 5$ $=$ $5\pi $
$E\right)$ $1=$ $15^{-}$ $1-$
$d\right)$ $17=$ $15$ n.5 $\bar{I} ^{x}\pi $

Other

Solution

Qanda teacher - shubapaul

option d is correct

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