Problem

$A$ A flagpole stands on a building and $a∩$
observer on a level ground is $300$ feet $xOm$
the base of the building. The angle $0f$
$eleVati0n$ of the bottom of the flagpole is $30^{°}$
and the height of the flagpole is $00$ feet. If
$θ$ 0 is the angle of elevation of the top of the
flagpole, then tan $θ$ is equal to
$\left(a\right)$ $\dfrac {2\sqrt{3} +1} {6}$ (b) $\dfrac {\sqrt{3} } {2}$
$\left(c\right)$ $1$ Ka $\left(d\right)$ $\dfrac {6\sqrt{3} +1} {6}$

10th-13th grade

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Solution

Qanda teacher - sinjoy

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