Problem

Solve $\left(a\right)\left(x-4\right)^{2}+5=\left(x+2\right)^{2}-\left(9-14x\right)$
$-1$ $\left(x-2\right)^{2}+9=\left(2x+1\right)^{2}-\left(5x-6\right)$
Solve $:\left(a\right)$ $\dfrac {2x-1} {5x+3}=\dfrac {2x+2} {5x+16}$
$0$ $\dfrac {4x+1} {3x+2}=\dfrac {4x+6} {3x+7}$
Solve $:\left(a\right)$ $\dfrac {x+2} {x+1}-\dfrac {x+2} {x-1}=\dfrac {x+5} {x^{2}-1}$
$\dfrac {2-x} {x+2}-\dfrac {2x-1} {x-2}=\dfrac {5x-1} {x^{2}-4}$

7th-9th grade

Algebra

Search count: 105

Solution

Qanda teacher - Liza

Student

but in my -2 is there

book

Qanda teacher - Liza

Let me check

yes there was an error dear ..sorry

i correct it

check

you understand?

Student

haa thank sir

Qanda teacher - Liza

Please evaluate and give your valuable feedback

Student

s sir but lastly somewhat I am not understanding

Qanda teacher - Liza

which part tell me specifically dear

i take common

in last

Student

in 6 step 3 u didn't write

Qanda teacher - Liza

x+2=0 hence x=-2

okay

i am doing again

Student

Kk sir

Qanda teacher - Liza

you understand now

Student

then what is the final answer sir

Qanda teacher - Liza

x=-2 or 1

Student

Kk sir

Qanda teacher - Liza

Okey then please evaluate

and if you have more questions then you can ask me separately

Student

kk

sir how

Qanda teacher - Liza

After evaluation you may ask me directly from preferred match section

Student

Kk then bye sir

Qanda teacher - Liza

Okey

Student

Sir how get coins sir

I have no coins to give u then how

Qanda teacher - Liza

just give ratings here.

Student

Kk s sir

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