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Solve $\left(a\right)\left(x-4\right)^{2}+5=\left(x+2\right)^{2}-\left(9-14x\right)$ $-1$ $\left(x-2\right)^{2}+9=\left(2x+1\right)^{2}-\left(5x-6\right)$ Solve $:\left(a\right)$ $\dfrac {2x-1} {5x+3}=\dfrac {2x+2} {5x+16}$ $0$ $\dfrac {4x+1} {3x+2}=\dfrac {4x+6} {3x+7}$ Solve $:\left(a\right)$ $\dfrac {x+2} {x+1}-\dfrac {x+2} {x-1}=\dfrac {x+5} {x^{2}-1}$ $\dfrac {2-x} {x+2}-\dfrac {2x-1} {x-2}=\dfrac {5x-1} {x^{2}-4}$
7th-9th grade
Algebra
Search count: 105
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Qanda teacher - Liza
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Student
but in my -2 is there
book
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Qanda teacher - Liza
Let me check
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yes there was an error dear ..sorry
i correct it
check
you understand?
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Student
haa thank sir
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Qanda teacher - Liza
Please evaluate and give your valuable feedback
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Student
s sir but lastly somewhat I am not understanding
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Qanda teacher - Liza
which part tell me specifically dear
i take common
in last
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Student
in 6 step 3 u didn't write
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Qanda teacher - Liza
x+2=0 hence x=-2
okay
i am doing again
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Student
Kk sir
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Qanda teacher - Liza
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you understand now
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Student
then what is the final answer sir
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Qanda teacher - Liza
x=-2 or 1
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Student
Kk sir
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Qanda teacher - Liza
Okey then please evaluate
and if you have more questions then you can ask me separately
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Student
kk
sir how
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Qanda teacher - Liza
After evaluation you may ask me directly from preferred match section
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Student
Kk then bye sir
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Qanda teacher - Liza
Okey
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Student
Sir how get coins sir
I have no coins to give u then how
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Qanda teacher - Liza
just give ratings here.
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Student
Kk s sir
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