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$8.6$ $35\pi $ $10.7810$ $\left(27\right)$ $7$ $8θ^{°}$ far $18$ ft a, F $\left(\pi =$ $-$ $3.14\right)$ $14$ fra $r=18$ $θ=80^{°}$ $\pi =3.14$ $1$ $=l=\dfrac {θ} {360}\times 2\pi x$ $l=\dfrac {80} {360}\times 2\times 3.14\times 18$ $=4\times 2\times 3.14=8\times 314$
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Qanda teacher - Saumyajeet
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