Symbol
Problem
$3.$ Equation of circle passing through $\left(-1,-2\right)$ and concentric with the circle $x^{2}+y^{2}+3x+4y+1=0$ $1\right)$ $x^{2}+y^{2}+3x+4y+6=0$ $2\right)$ $x^{2}+y^{2}-3x-4y+6=0$ $3\right)$ $x^{2}+y^{2}+3x+4y-6=0$ $4\right)$ $x^{2}+y^{2}+3x-4y-6=0$
Geometry
Solution
Qanda teacher - Mukesh
Student
samaz me Nahi aya
I do not understand