Symbol
Problem
$-$ $\left(48$ $82$ $\left($ $49^{x}=7^{3}$ $\left(1\right)$ $2^{x+2}+2^{x-1}=9$ (m $2^{x--2^{x-2}}=48$ $\left(iy\right)$ $2^{4x}.4^{3x-1}$ $=\dfrac {4^{2x}} {2^{3x}}$ $\left(y\right)$ $9\times 81^{x}=27^{2-x}$ $\left(M\right)$ $2^{5x+4}+2^{9}=2^{10}$ $\left(M1\right)$ $6$ $2x+4=3^{3x}2^{x+8}$
Algebra
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Solution
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Student
mam 4 no sum m problam h