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$1^{2}$ $2$ $3$ Solve the following simultaneous equations using Cramer's rule. $\left(1\right)$ $3x-4y=10:4x+3y=5$ $\left(2\right)$ $4x+3y-4=0:6x=8$ $5y$ $\left(3\right)$ $x+2y=-1:2x-3y=12$ $\left(4\right)$ $6x-4y=-12:8x-3y=-2$ $\left(5\right)$ $4m+6n=54:3m+2n=28$ $\left(6\right)$ $2x+3y=2:x-\dfrac {y} {2}=\dfrac {1} {2}$
10th-13th grade
Algebra
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Qanda teacher - harshit
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tqsm for asking
sir