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$2$ Find the sum of the first 6 terms of geometric $sCFcs$ $\dfrac {1} {4},\dfrac {1} {2},1,$ ... $Solution$ $a_{1}\dfrac {1} {4}$ $n=6$ $r=\dfrac {\dfrac {1} {2}} {\bar{4} }=\dfrac {4} {2}=2$ Substitute these values $0$ the formula: $S_{n}=$ $\dfrac {a_{1}\left(1-r^{n}\right)} {1-r}$ $S_{6}=\dfrac {\dfrac {1} {4}\left(1-2^{6}\right)} {1-2}$ $s_{6}=\dfrac {\dfrac {1} {4}\left(1-64\right)} {-1}$ $\dfrac {1} {4}\left(-63\right)$ $S_{6}=$ $\bar{-1} $ $S_{6}=$ $\dfrac {-\dfrac {63} {4}} {-1}$ $S_{6}=\dfrac {63} {4}$
10th-13th grade
Geometry
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Qanda teacher - saikumar
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