Problem

$\left(4ma\pi ks\right)$
$2$ The Intermediate-Value Theorem states that if $4$ function $f$ is continuous on closed
interval $\left(a,b\right)$ and k is any number between $f\left(a\right)$ and $f\left(b\right)$ inclusive, then there is at
least one number $x$ in the interval $a.b$ such that $f\left(x\right)=k$
$\left(a\right)$ Give a geometrical interpretation of the Intermediate-Value Theorem.
(b) Use the Intermediate-Value Theorem to show that the equation $x^{3}+x^{2}-2x=1$
has at least one solution in the $intarma1$ $-1$ $1\right)$
$\left(2+3=5ma\pi ks\right)$

Calculus

Solution

Qanda teacher - Nivas

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