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10th-13th gradeTrigonometry
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search-thumbnail-If $sccθ-cos6$ $θ-cosθ=1$ then $tan^{2}$ $\dfrac {θ} {2}=$
10th-13th gradeTrigonometry
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search-thumbnail-$9$ Ef $secθ-cosθ=1$ then $tan^{2}\dfrac {θ} {2}=$ $1\right)$ $\sqrt{5} +2$ $2\right)$ $\sqrt{5} -2$ $3\right)$ $2-\sqrt{5} 4\right)0$
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