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Formula
Solve the equation
Answer
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Calculate the differentiation
Answer
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Graph
$y = \dfrac { 1 } { 2 } x - 1$
$x$-intercept
$\left ( 2 , 0 \right )$
$y$-intercept
$\left ( 0 , - 1 \right )$
$y = \dfrac{ 1 }{ 2 } x-1$
$x = 2 y + 2$
$ $ Solve a solution to $ x$
$y = \color{#FF6800}{ \dfrac { 1 } { 2 } } \color{#FF6800}{ x } - 1$
$ $ Calculate the multiplication expression $ $
$y = \color{#FF6800}{ \dfrac { x } { 2 } } - 1$
$\color{#FF6800}{ y } = \color{#FF6800}{ \dfrac { x } { 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 1 }$
$ $ Multiply both sides by the least common multiple for the denominators to eliminate the fraction $ $
$\color{#FF6800}{ 2 } \color{#FF6800}{ y } = \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 2 }$
$2 y = \color{#FF6800}{ x } - 2$
$ $ Move $ x $ term to the left side and change the sign $ $
$2 y - x = - 2$
$\color{#FF6800}{ 2 } \color{#FF6800}{ y } - x = - 2$
$ $ Move the rest of the expression except $ x $ term to the right side and replace the sign $ $
$- x = - 2 \color{#FF6800}{ - } \left ( \color{#FF6800}{ 2 } \color{#FF6800}{ y } \right )$
$- x = \color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ - } \left ( \color{#FF6800}{ 2 } \color{#FF6800}{ y } \right )$
$ $ Organize the expression $ $
$- x = \color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ y } \color{#FF6800}{ - } \color{#FF6800}{ 2 }$
$\color{#FF6800}{ - } \color{#FF6800}{ x } = \color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ y } \color{#FF6800}{ - } \color{#FF6800}{ 2 }$
$ $ Change the sign of both sides of the equation $ $
$x = 2 y + 2$
$\dfrac {d } {d x } {\left( y \right)} = \dfrac { 1 } { 2 }$
Calculate the differentiation of the logarithmic function
$\dfrac {d } {d \color{#FF6800}{ x } } {\left( \color{#FF6800}{ \dfrac { 1 } { 2 } } \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 1 } \right)}$
$ $ Calculate the differentiation $ $
$\color{#FF6800}{ \dfrac { 1 } { 2 } }$
$ $ 그래프 보기 $ $
Linear function
Solution search results
search-thumbnail-In the following problem $a,b,$ b,and c represent REAL NUMBERS. The derivative of $g\left(x\right)=log _{a}\left(bx\right)+cx^{2}is$ $○$ $g^{1}\left(x\right)=\right)dfrac\left(b\right)log _{-}a\left(bx\right)\right)\left(N1n$ $a\right)+2cx1\right)$ $○$ $\left(g\left(x\right)=\right)dtracb$ $loga\left(bx\right)+2c\times \right)Nln$ a}\) $○$ $g^{'}\left(x\right)=\left(dfraC\left(a\right)log _{-}a\left(bx\right)\right)\left(ln$ $\right)+2c\times 1\right)\right)$ $○$ $g^{1}\left(x\right)=\left(dfrac\left(b$ $log _{-}a\left(bx\right)\right)\left(ln$ $a1\right)$ $○$ $\left(\left(g^{1}\left(x\right)=b$ $log _{-}a\left(bx\right)+2cx1\right)$ $○$ $g\left(x\right)=\left(dfrac\left(b$ $log _{-}a\left(bx\right)\right)\left(1ln$ $a|+2c1\right)$
Calculus
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search-thumbnail-$y=x$ $y=3x$ $y=2x+1$ $y=\dfrac {1} {2}x-1$ $y=-\dfrac {3} {2}x-3$ $y=5$ $x=-2$ $y.1=2\left(x-3\right)$ $y-2=1\left(\dfrac {1} {2}x$ $+2\right)$
7th-9th grade
Other
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search-thumbnail-$\left(int|imits$ $-0a1\left(1-\times n_{2}{\right)_{3}}^{n}$ $x^{A}3dx=7\right)$ $\left($ $frac\left(1\right)\left(40\right)\right)$ $\left($ $\left(troc\left(1\right)\left(35\right)\right)$ $\left(troc\left(1\right)\left(30\right)\right)$ $\left(tr0c\left(1\right)\left(25\right)\right)$
Calculus
Check solution
search-thumbnail-Which of the following rational numbers are equivalent? $0Ptionsy$ A \frac{5}{6}, \frac{30}{36} B $s\sqrt{rac\left(} -2\right)\left(3\right)\sqrt{1rac} \sqrt{4\right)16\right)4} $ C $s\sqrt{11aC\left(} -4\right)1-7b,\sqrt{1rac\left(16\sqrt{35\right)9} } $ D \frac{1}{2},\frac{3}{8}
7th-9th grade
Other
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