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$x + 9 \leq \color{#FF6800}{ 4 } \color{#FF6800}{ x } - 3$

$ $ Move the variable to the left-hand side and change the symbol $ $

$x + 9 \color{#FF6800}{ - } \color{#FF6800}{ 4 } \color{#FF6800}{ x } \leq - 3$

$x \color{#FF6800}{ + } \color{#FF6800}{ 9 } - 4 x \leq - 3$

$ $ Move the constant to the right side and change the sign $ $

$x - 4 x \leq - 3 \color{#FF6800}{ - } \color{#FF6800}{ 9 }$

$\color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 4 } \color{#FF6800}{ x } \leq - 3 - 9$

$ $ Organize the expression $ $

$\color{#FF6800}{ - } \color{#FF6800}{ 3 } \color{#FF6800}{ x } \leq - 3 - 9$

$- 3 x \leq \color{#FF6800}{ - } \color{#FF6800}{ 3 } \color{#FF6800}{ - } \color{#FF6800}{ 9 }$

$ $ Find the sum of the negative numbers $ $

$- 3 x \leq \color{#FF6800}{ - } \color{#FF6800}{ 12 }$

$\color{#FF6800}{ - } \color{#FF6800}{ 3 } \color{#FF6800}{ x } \leq \color{#FF6800}{ - } \color{#FF6800}{ 12 }$

$ $ Change the symbol of the inequality of both sides, and reverse the symbol of the inequality to the opposite direction $ $

$3 x \geq 12$

$\color{#FF6800}{ 3 } \color{#FF6800}{ x } \geq \color{#FF6800}{ 12 }$

$ $ Divide both sides by the same number $ $

$\color{#FF6800}{ x } \geq \color{#FF6800}{ 4 }$