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Formula
Solve the inequality
Answer
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Graph
$x + 9 \leq 4 x - 3$
$x + 9 \leq 4 x - 3$
Solution of inequality
$x \geq 4$
$x+9 \leq 4x-3$
$x \geq 4$
$ $ Solve a solution to $ x$
$x + 9 \leq \color{#FF6800}{ 4 } \color{#FF6800}{ x } - 3$
$ $ Move the variable to the left-hand side and change the symbol $ $
$x + 9 \color{#FF6800}{ - } \color{#FF6800}{ 4 } \color{#FF6800}{ x } \leq - 3$
$x \color{#FF6800}{ + } \color{#FF6800}{ 9 } - 4 x \leq - 3$
$ $ Move the constant to the right side and change the sign $ $
$x - 4 x \leq - 3 \color{#FF6800}{ - } \color{#FF6800}{ 9 }$
$\color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 4 } \color{#FF6800}{ x } \leq - 3 - 9$
$ $ Organize the expression $ $
$\color{#FF6800}{ - } \color{#FF6800}{ 3 } \color{#FF6800}{ x } \leq - 3 - 9$
$- 3 x \leq \color{#FF6800}{ - } \color{#FF6800}{ 3 } \color{#FF6800}{ - } \color{#FF6800}{ 9 }$
$ $ Find the sum of the negative numbers $ $
$- 3 x \leq \color{#FF6800}{ - } \color{#FF6800}{ 12 }$
$\color{#FF6800}{ - } \color{#FF6800}{ 3 } \color{#FF6800}{ x } \leq \color{#FF6800}{ - } \color{#FF6800}{ 12 }$
$ $ Change the symbol of the inequality of both sides, and reverse the symbol of the inequality to the opposite direction $ $
$3 x \geq 12$
$\color{#FF6800}{ 3 } \color{#FF6800}{ x } \geq \color{#FF6800}{ 12 }$
$ $ Divide both sides by the same number $ $
$\color{#FF6800}{ x } \geq \color{#FF6800}{ 4 }$
$ $ 그래프 보기 $ $
Inequality
Solution search results
search-thumbnail-$7x^{2}$ $-3x$ $-3x+$ $9$ 
$+3x^{2}+6x-10$
7th-9th grade
Algebra
search-thumbnail-$\dfrac {x^{2}-9} {x^{3}+27}$ $t$ $\dfrac {5} {2xcx^{2}-32c+9}$ $-\dfrac {x-3} {x^{2}-3x+9}$
7th-9th grade
Algebra
search-thumbnail-$2°$ Quadrilateral $ABCD$ is square. Find $x^{4}4$ 
$AK$ $\left(6x+9\longdiv{°}-.\right)B$ 
$54^{°}$ 
$D$ $C$
7th-9th grade
Geometry
search-thumbnail-c) $x+3$ $+3x+9^{+\dfrac {x-3} {x^{2}-3x+9}-\dfrac {54} {x^{4}+9x^{2}+81}}$
7th-9th grade
Other
search-thumbnail-B. Find the derivative of $y$ with respect to $x:$ 
$5.$ $y=\dfrac {\left(x+3\right)\left(x-3\right)} {\left(x^{2}6x+9\longdiv{}1}$ $-$
10th-13th grade
Calculus
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