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Formula
Solve the equation
Answer
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Graph
$y = x + 2$
$y = 5$
$x$-intercept
$\left ( - 2 , 0 \right )$
$y$-intercept
$\left ( 0 , 2 \right )$
$x+2 = 5$
$x = 3$
$ $ Solve a solution to $ x$
$x \color{#FF6800}{ + } \color{#FF6800}{ 2 } = 5$
$ $ Move the constant to the right side and change the sign $ $
$x = 5 \color{#FF6800}{ - } \color{#FF6800}{ 2 }$
$x = \color{#FF6800}{ 5 } \color{#FF6800}{ - } \color{#FF6800}{ 2 }$
$ $ Subtract $ 2 $ from $ 5$
$x = \color{#FF6800}{ 3 }$
$ $ 그래프 보기 $ $
Graph
Solution search results
search-thumbnail-Part $2:$ Justify each statement 
Given $2\left(3x+1\right)=5x+14$ 
Statements Reasons 
$2\left(3x+1\right)=5x+14$ GIVEN 
$6x+2=5x+14$ $6.$ 
$x+2=14$ $\bar{7} $ 
$x=12$ $8$
7th-9th grade
Geometry
search-thumbnail-$4$ $10x+2=$ $5x+27$
1st-6th grade
Calculus
search-thumbnail-$1$ $-$ $1$ 
$4$ $10x+2=$ $5x+27$
1st-6th grade
Calculus
search-thumbnail-$3.$ $5x-12=13$ 
$4.$ $10x+2=5x+27$
1st-6th grade
Algebra
search-thumbnail-Group $B$ 
$C.M$ of $8$ $12$ and $16$ 
$1\right)$ Find the L.C.M 
$2\right)$ Solve: $9x+2=5x+14$ 
$3\right)$ Multiply: $2a\left(3a-7\right)$
1st-6th grade
Other
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