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Formula

Solve the equation

Answer

Graph

$y = x + 2$

$y = 5$

$x$Intercept

$\left ( - 2 , 0 \right )$

$y$Intercept

$\left ( 0 , 2 \right )$

$x+2 = 5$

$x = 3$

$ $ Solve a solution to $ x$

$x \color{#FF6800}{ + } \color{#FF6800}{ 2 } = 5$

$ $ Move the constant to the right side and change the sign $ $

$x = 5 \color{#FF6800}{ - } \color{#FF6800}{ 2 }$

$x = \color{#FF6800}{ 5 } \color{#FF6800}{ - } \color{#FF6800}{ 2 }$

$ $ Subtract $ 2 $ from $ 5$

$x = \color{#FF6800}{ 3 }$

Solution search results

$\sqrt{x+2} =5$

10th-13th grade

Algebra

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$\sqrt{x+2} =5$ $I$

10th-13th grade

Algebra

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$1^{°}N$ $-14$ $11N$ $\left(1\right)rx+2=5$

1st-6th grade

Geometry

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$2$ $=$ $3x+2=5$ find x.

10th-13th grade

Algebra

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$3$ $ \begin{cases} x=5y-9 \\ 8x+2=5y \end{cases} $

10th-13th grade

Other

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$x-y$ $t20$ $\dfrac {x-y} {2xy}$ $-1$ $5$ $3^{\right)}$ $3z+43f=$ $0$ $x\dfrac {-y} {a}=$ $1$ $2x+2=S$

Algebra

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