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Formula
Graph
$y = x ^ { 3 } - 6 x ^ { 2 } + 13 x - 10$
$y = 0$
$x$Intercept
$\left ( 2 , 0 \right )$
$y$Intercept
$\left ( 0 , - 10 \right )$
Derivative
$3 x ^ { 2 } - 12 x + 13$
Seconde derivative
$6 x - 12$
Point of inflection
$\left ( 2 , 0 \right )$
$x ^{ 3 } -6x ^{ 2 } +13x-10 = 0$
$ $ 그래프 보기 $ $
Graph
Solution search results
search-thumbnail-$3.$ If $a,β,γ$ are the roots of $x^{3}-6x^{2}+13x-10=0$ Form the equation with roots 
$aβ,βr.ra.$
1st-6th grade
Algebra
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