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Formula
Solve the cubic equation
Answer
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Graph
$y = x ^ { 3 } - 1$
$y = 0$
$x$Intercept
$\left ( 1 , 0 \right )$
$y$Intercept
$\left ( 0 , - 1 \right )$
Derivative
$3 x ^ { 2 }$
Seconde derivative
$6 x$
Local Maximum
$\left ( 0 , - 1 \right )$
Point of inflection
$\left ( 0 , - 1 \right )$
$x ^{ 3 } -1 = 0$
$x = 1$
Solve the cubic equation
$\color{#FF6800}{ x } ^ { \color{#FF6800}{ 3 } } \color{#FF6800}{ - } \color{#FF6800}{ 1 } = \color{#FF6800}{ 0 }$
$ $ Organize the expression $ $
$\color{#FF6800}{ x } ^ { \color{#FF6800}{ 3 } } = \color{#FF6800}{ 0 } \color{#FF6800}{ + } \color{#FF6800}{ 1 }$
$x ^ { 3 } = \color{#FF6800}{ 0 } + 1$
$ $ 0 does not change when you add or subtract $ $
$x ^ { 3 } = 1$
$\color{#FF6800}{ x } ^ { \color{#FF6800}{ 3 } } = \color{#FF6800}{ 1 }$
$ $ Do the cube root on both sides of the equation $ $
$\color{#FF6800}{ x } = \sqrt[ \color{#FF6800}{ 3 } ]{ \color{#FF6800}{ 1 } }$
$x = \sqrt[ \color{#FF6800}{ 3 } ]{ \color{#FF6800}{ 1 } }$
$n $ square root of 1 is 1 $ $
$x = \color{#FF6800}{ 1 }$
Solution search results
search-thumbnail-x^{3}-1=0
$x^{3}-1=0$
1st-6th grade
Algebra
search-thumbnail-x-1=0
$x-1=0$
7th-9th grade
Other
search-thumbnail-x^{3}+4x-1=0
$x^{3}+4x-1=0$
10th-13th grade
Algebra
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