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$∠$ $F$ From the sum $ot$ $x^{A}\left(2\right)-8$ with $3x-12$ subtract the sum $ofx-9$ with $3x-x^{A}\left(2\right)$ Multinlication takes place $\left(2\times A$ $\left(2\right)+5x+21\right)\left(x-$ $5\right)=$ #Please provide solution by using math formula.

Domain of the function, $f\left(x\right)=\sqrt{1-\bar{\sqrt{\left(x^{2}} -4x+5\right)} } $ is $\left(1\right)$ $0$ $\left(2\right)$ $\left(3\right)$ $\left(2\right)$ $\left(4\right)$ $8-121\sqrt{} $ $1-\sqrt{1} ^{16}$

Using the \emph{removal of first derivative} method, the differential equation \( \frac{d^{2}y} $\left(d\times n$ $\left(2\right)\right)+P|ffac\left(dy\right)\left(dx\right)+Qy=F$ $dx\right)+Qy=RN\right)$ is transformed as \). For, the differential equation \frac{d^{2}y} $\left(d^{n}\left(2\right)y\right)$ $dx$ $\left(2\right)+2x$ $\left(0C\left(dy\right)\left(dx\right)+\left(x$ $2+1\right)y=\times n3+3x\right)$ the value of $\left(11\right)$

#This question was automatically translated by Qanda $A1$ The proper process $t09$ obtain $m$ knowing that $ts$ local minimum $s$ $s$ $nclonf\left(x\right)=x^{n}\left(2\right)+\times \left(m\right)$ $\left(x\right)is$ Select a $=2e$ in the funclon

$11At0$ $10$ flag is fixed vertically at the top of $a$ building, from a point located $60$ $m$ From the base of the building, the elevation angles to the foot $\times 010to$ the top of the to the flag are $21A$ $ \begin{cases} ° \\ 50\right)y35<3\right) \end{cases} $ $10A$ $\left(2\right)$ Find the measure of the to Measure of the flagpole is $128115m2Da21250\pi $

ANALYTICAL GEOMETRY (ESSENTIAL $EARN|NG\right)$ Find the equation of the line that passes through the points $A\left(7.1\right)$ and $B$ $\left(3.8\right)\left(y-y1\right)=k\left(2-\right)\left(x$ $\left(2\right)-x$ $\left(2\right)\right)\left(x-\times \left(1\right)\right)$ $1-B\left(3.8\right)\left(y$ - $\right)=\times \left(1-8\right)\left(7$ $3\right)\left(x-7\right)$ $4x+\left(y-1\right)=\times \left(-7\right)\left(4\right)\left(x-7\right)2=2$ $4\left(7.1\right)4\left(y-$ $\right)=-7\left(x-7\right)=04→14y-4=-7x+49-107x$ $+4y-4-49=07x+4y-53=0=43$