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$\dfrac {x^{2}-2x+3} {x^{2}-10x+}25$

$∠$ $F$ From the sum $ot$ $x^{A}\left(2\right)-8$ with $3x-12$ subtract the sum $ofx-9$ with $3x-x^{A}\left(2\right)$ Multinlication takes place $\left(2\times A$ $\left(2\right)+5x+21\right)\left(x-$ $5\right)=$ #Please provide solution by using math formula.

$\dfrac {x^{2}-x-20} {x^{2}-10x+25}x\dfrac {x^{3}-27} {x^{2}+7\times +12}$

$2.$ $f\left(x\right)=\dfrac {x^{2}-10x+25} {x+5}$

$x^{2}-10x+1=-20$ $x^{2}-10x+1-1=-20-1$ $x^{2}-10x$ $=-21$ $\left(-\dfrac {10} {2}\right)^{2}=\left(-5\right)^{2}=25$ $x^{2}-10x+25=-20+25$

$1$ If $y=x^{3}-5x^{2}+10x+25,$ find $\dfrac {d^{2}y} {dx^{2}}$ $11$ $S0lati0n$ $:$ $y=x^{3}-5x^{2}+10x+25$ $1s$ $∴\dfrac {dy} {dx}=3x^{2}-10x+10$ $:\dfrac {d^{2}y} {dx^{2}}=6x-10$ $1s$ $144$