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Graph
$x ^ { 2 } + y ^ { 2 } - 2 x + 4 y - 4 = 0$
$x$Intercept
$\left ( 1 + \sqrt{ 5 } , 0 \right )$, $\left ( 1 - \sqrt{ 5 } , 0 \right )$
$y$Intercept
$\left ( 0 , - 2 \sqrt{ 2 } - 2 \right )$, $\left ( 0 , - 2 + 2 \sqrt{ 2 } \right )$
Center
$\left ( 1 , - 2 \right )$
Radius
$3$
Standard form
$\left ( x - 1 \right ) ^ { 2 } + \left ( y - \left ( - 2 \right ) \right ) ^ { 2 } = 3 ^ { 2 }$
$x ^{ 2 } +y ^{ 2 } -2x+4y-4 = 0$
$ $ 그래프 보기 $ $
Graph of Circle
Solution search results
search-thumbnail-The equation of a parabola of given directrix $x-y=2$ and 
focus at origin is 
$x^{2}+y^{2}+2xy+4x-4y-4=0$ 
$x^{2}+y^{2}-2xy+4x-4y-4=0$ 
$x^{2}+y^{2}+2xy-4x+4y+4=0$ 
$x^{2}+y^{2}+2xy+4x-4y+4=0$
10th-13th grade
Algebra
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