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$\left(ff\left(x-1\right)=x^{2}$ $,$ then $f\left(x+1\right)=$ $1\right)x^{2}+2x+1$ $2\right)2x^{2}+4x+1$ $3\right)x^{2}-4x+4$ $4\right)x^{2}+4x+4$

$∠$ $F$ From the sum $ot$ $x^{A}\left(2\right)-8$ with $3x-12$ subtract the sum $ofx-9$ with $3x-x^{A}\left(2\right)$ Multinlication takes place $\left(2\times A$ $\left(2\right)+5x+21\right)\left(x-$ $5\right)=$ #Please provide solution by using math formula.

#This question was automatically translated by Qanda $A1$ The proper process $t09$ obtain $m$ knowing that $ts$ local minimum $s$ $s$ $nclonf\left(x\right)=x^{n}\left(2\right)+\times \left(m\right)$ $\left(x\right)is$ Select a $=2e$ in the funclon

$x^{2}+4x+4\geq 9$

Using the \emph{removal of first derivative} method, the differential equation \( \frac{d^{2}y} $\left(d\times n$ $\left(2\right)\right)+P|ffac\left(dy\right)\left(dx\right)+Qy=F$ $dx\right)+Qy=RN\right)$ is transformed as \). For, the differential equation \frac{d^{2}y} $\left(d^{n}\left(2\right)y\right)$ $dx$ $\left(2\right)+2x$ $\left(0C\left(dy\right)\left(dx\right)+\left(x$ $2+1\right)y=\times n3+3x\right)$ the value of $\left(11\right)$

$x+2\right)\left(8-4$ $=$ $2+y\times +4$ $x$