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Solve the equation
Answer
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$x \div y = \dfrac { y } { x }$
$x \div y = \dfrac{ y }{ x }$
$\begin{cases} x ^ { 2 } = y ^ { 2 } \\ y \neq 0 \\ x \neq 0 \end{cases}$
Solve the fractional equation
$\color{#FF6800}{ x } \color{#FF6800}{ \div } \color{#FF6800}{ y } = \color{#FF6800}{ \dfrac { y } { x } }$
$ $ Reverse the left and right terms of the equation (or inequality) $ $
$\color{#FF6800}{ \dfrac { y } { x } } = \color{#FF6800}{ x } \color{#FF6800}{ \div } \color{#FF6800}{ y }$
$\color{#FF6800}{ \dfrac { y } { x } } = \color{#FF6800}{ x } \color{#FF6800}{ \div } \color{#FF6800}{ y }$
$ $ If $ \frac{a(x)}{b(x)} = c(x) $ is valid, it is $ \begin{cases} a(x) = b(x) c(x) \\ b(x) \ne 0 \end{cases}$
$\begin{cases} \color{#FF6800}{ y } = \color{#FF6800}{ x } \left ( \color{#FF6800}{ x } \color{#FF6800}{ \div } \color{#FF6800}{ y } \right ) \\ \color{#FF6800}{ x } \neq \color{#FF6800}{ 0 } \end{cases}$
$\begin{cases} \color{#FF6800}{ y } = \color{#FF6800}{ x } \left ( \color{#FF6800}{ x } \color{#FF6800}{ \div } \color{#FF6800}{ y } \right ) \\ \color{#FF6800}{ x } \neq \color{#FF6800}{ 0 } \end{cases}$
$ $ Simplify the expression $ $
$\begin{cases} \color{#FF6800}{ y } = \color{#FF6800}{ \dfrac { x ^ { 2 } } { y } } \\ \color{#FF6800}{ x } \neq \color{#FF6800}{ 0 } \end{cases}$
$\begin{cases} \color{#FF6800}{ y } = \color{#FF6800}{ \dfrac { x ^ { 2 } } { y } } \\ x \neq 0 \end{cases}$
$ $ Reverse the left and right terms of the equation (or inequality) $ $
$\begin{cases} \color{#FF6800}{ \dfrac { x ^ { 2 } } { y } } = \color{#FF6800}{ y } \\ x \neq 0 \end{cases}$
$\begin{cases} \color{#FF6800}{ \dfrac { x ^ { 2 } } { y } } = \color{#FF6800}{ y } \\ x \neq 0 \end{cases}$
$ $ If $ \frac{a(x)}{b(x)} = c(x) $ is valid, it is $ \begin{cases} a(x) = b(x) c(x) \\ b(x) \ne 0 \end{cases}$
$\begin{cases} \begin{cases} \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } = \color{#FF6800}{ y } \color{#FF6800}{ y } \\ \color{#FF6800}{ y } \neq \color{#FF6800}{ 0 } \end{cases} \\ x \neq 0 \end{cases}$
$\begin{cases} \begin{cases} \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } = \color{#FF6800}{ y } \color{#FF6800}{ y } \\ \color{#FF6800}{ y } \neq \color{#FF6800}{ 0 } \end{cases} \\ \color{#FF6800}{ x } \neq \color{#FF6800}{ 0 } \end{cases}$
$ $ If there is a system of equations (inequality) in the system of equations (inequality), take it out. $ $
$\begin{cases} \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } = \color{#FF6800}{ y } \color{#FF6800}{ y } \\ \color{#FF6800}{ y } \neq \color{#FF6800}{ 0 } \\ \color{#FF6800}{ x } \neq \color{#FF6800}{ 0 } \end{cases}$
$\begin{cases} \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } = \color{#FF6800}{ y } \color{#FF6800}{ y } \\ \color{#FF6800}{ y } \neq \color{#FF6800}{ 0 } \\ \color{#FF6800}{ x } \neq \color{#FF6800}{ 0 } \end{cases}$
$ $ Simplify the expression $ $
$\begin{cases} \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } = \color{#FF6800}{ y } ^ { \color{#FF6800}{ 2 } } \\ \color{#FF6800}{ y } \neq \color{#FF6800}{ 0 } \\ \color{#FF6800}{ x } \neq \color{#FF6800}{ 0 } \end{cases}$
$ $ 그래프 보기 $ $
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Solution search results
search-thumbnail-In the following problem $a,b,$ b,and c represent REAL NUMBERS. The derivative of $g\left(x\right)=log _{a}\left(bx\right)+cx^{2}is$ $○$ $g^{1}\left(x\right)=\right)dfrac\left(b\right)log _{-}a\left(bx\right)\right)\left(N1n$ $a\right)+2cx1\right)$ $○$ $\left(g\left(x\right)=\right)dtracb$ $loga\left(bx\right)+2c\times \right)Nln$ a}\) $○$ $g^{'}\left(x\right)=\left(dfraC\left(a\right)log _{-}a\left(bx\right)\right)\left(ln$ $\right)+2c\times 1\right)\right)$ $○$ $g^{1}\left(x\right)=\left(dfrac\left(b$ $log _{-}a\left(bx\right)\right)\left(ln$ $a1\right)$ $○$ $\left(\left(g^{1}\left(x\right)=b$ $log _{-}a\left(bx\right)+2cx1\right)$ $○$ $g\left(x\right)=\left(dfrac\left(b$ $log _{-}a\left(bx\right)\right)\left(1ln$ $a|+2c1\right)$
Calculus
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search-thumbnail-$→$ $10$ The reciprocal of $x$ is $A.\dfrac {x-} {x}$ $x-y$ $-$ $B,\dfrac {x-} {x}$ $\dfrac {x-y} {x}$ $c\dfrac {2} {x-y}$ D. $\dfrac {y} {x-2}$
10th-13th grade
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