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$Z$ $x$ $12$ $60^{0}$ $y$ $\times =$ = $y=$ $\vec{z} =$

$12.$ $x^{2}$ $=y^{b}=x^{c}7y^{2}=xy$ $\dfrac {2} {b}=\dfrac {1} {a}+\dfrac {1} {c}$ $1$ $\left(1fx^{2}=y^{b}=z^{c}$ and $y^{2}=xy$ xy, show that $\dfrac {2} {b}$ $=\dfrac {1} {a}+\dfrac {1} {c}$

$3$ $y$ $x$ $8$ $94$ $3$ $20.$ $x=$ $y=$