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Formula
Expand the expression
Answer
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Factorize the expression
Answer
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$ax ^{ 2 } -4a-x ^{ 2 } +4$
$\left ( a - 1 \right ) x ^ { 2 } - 4 a + 4$
Organize polynomials
$\color{#FF6800}{ a } \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 4 } \color{#FF6800}{ a } \color{#FF6800}{ - } \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ + } \color{#FF6800}{ 4 }$
$ $ Organize the similar terms $ $
$\left ( \color{#FF6800}{ a } \color{#FF6800}{ - } \color{#FF6800}{ 1 } \right ) \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ + } \left ( \color{#FF6800}{ - } \color{#FF6800}{ 4 } \color{#FF6800}{ a } \color{#FF6800}{ + } \color{#FF6800}{ 4 } \right )$
$\left ( \color{#FF6800}{ a } \color{#FF6800}{ - } \color{#FF6800}{ 1 } \right ) \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ + } \left ( \color{#FF6800}{ - } \color{#FF6800}{ 4 } \color{#FF6800}{ a } \color{#FF6800}{ + } \color{#FF6800}{ 4 } \right )$
$ $ Get rid of unnecessary parentheses $ $
$\left ( \color{#FF6800}{ a } \color{#FF6800}{ - } \color{#FF6800}{ 1 } \right ) \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 4 } \color{#FF6800}{ a } \color{#FF6800}{ + } \color{#FF6800}{ 4 }$
$\left ( a - 1 \right ) \left ( x - 2 \right ) \left ( x + 2 \right )$
Arrange the expression in the form of factorization..
$\color{#FF6800}{ a } \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 4 } \color{#FF6800}{ a } \color{#FF6800}{ - } \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ + } \color{#FF6800}{ 4 }$
$ $ Expand the expression $ $
$\left ( \color{#FF6800}{ a } \color{#FF6800}{ - } \color{#FF6800}{ 1 } \right ) \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 4 } \color{#FF6800}{ a } \color{#FF6800}{ + } \color{#FF6800}{ 4 }$
$\left ( \color{#FF6800}{ a } \color{#FF6800}{ - } \color{#FF6800}{ 1 } \right ) \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 4 } \color{#FF6800}{ a } \color{#FF6800}{ + } \color{#FF6800}{ 4 }$
$ $ Do factorization $ $
$\left ( \color{#FF6800}{ a } \color{#FF6800}{ - } \color{#FF6800}{ 1 } \right ) \left ( \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 2 } \right ) \left ( \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 2 } \right )$
Solution search results
search-thumbnail-$It$ $f\left(x\right)=2x^{2}$ $-3$ then $f\left(x+a\right)$ $=7$ 
F. $2x^{2}+2ax+2a^{2}-3$ 
G. $2x^{2}$ $+4ax+2a^{2}$ $-3$ 
+ 
H. $2x^{2}$ $-4ax+2a^{2}$ $-3$ 
$1.$ $4x^{2}$ $+8ax+4a^{2}$ $-3$ 
K. $4x^{2}$ $+4ax+4a^{2}$ $-3$
10th-13th grade
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