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Formula
Expand the expression
Answer
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Factorize the expression
Answer
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$a ^{ 2 } -2a ^{ 3 } +3a ^{ 4 } -4a ^{ 5 } +6a ^{ 6 }$
$6 a ^ { 6 } - 4 a ^ { 5 } + 3 a ^ { 4 } - 2 a ^ { 3 } + a ^ { 2 }$
Organize polynomials
$\color{#FF6800}{ a } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ a } ^ { \color{#FF6800}{ 3 } } \color{#FF6800}{ + } \color{#FF6800}{ 3 } \color{#FF6800}{ a } ^ { \color{#FF6800}{ 4 } } \color{#FF6800}{ - } \color{#FF6800}{ 4 } \color{#FF6800}{ a } ^ { \color{#FF6800}{ 5 } } \color{#FF6800}{ + } \color{#FF6800}{ 6 } \color{#FF6800}{ a } ^ { \color{#FF6800}{ 6 } }$
$ $ Sort the polynomial expressions in descending order $ $
$\color{#FF6800}{ 6 } \color{#FF6800}{ a } ^ { \color{#FF6800}{ 6 } } \color{#FF6800}{ - } \color{#FF6800}{ 4 } \color{#FF6800}{ a } ^ { \color{#FF6800}{ 5 } } \color{#FF6800}{ + } \color{#FF6800}{ 3 } \color{#FF6800}{ a } ^ { \color{#FF6800}{ 4 } } \color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ a } ^ { \color{#FF6800}{ 3 } } \color{#FF6800}{ + } \color{#FF6800}{ a } ^ { \color{#FF6800}{ 2 } }$
$a ^ { 2 } \left ( 6 a ^ { 4 } - 4 a ^ { 3 } + 3 a ^ { 2 } - 2 a + 1 \right )$
Arrange the expression in the form of factorization..
$\color{#FF6800}{ a } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ a } ^ { \color{#FF6800}{ 3 } } \color{#FF6800}{ + } \color{#FF6800}{ 3 } \color{#FF6800}{ a } ^ { \color{#FF6800}{ 4 } } \color{#FF6800}{ - } \color{#FF6800}{ 4 } \color{#FF6800}{ a } ^ { \color{#FF6800}{ 5 } } \color{#FF6800}{ + } \color{#FF6800}{ 6 } \color{#FF6800}{ a } ^ { \color{#FF6800}{ 6 } }$
$ $ Expand the expression $ $
$\color{#FF6800}{ 6 } \color{#FF6800}{ a } ^ { \color{#FF6800}{ 6 } } \color{#FF6800}{ - } \color{#FF6800}{ 4 } \color{#FF6800}{ a } ^ { \color{#FF6800}{ 5 } } \color{#FF6800}{ + } \color{#FF6800}{ 3 } \color{#FF6800}{ a } ^ { \color{#FF6800}{ 4 } } \color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ a } ^ { \color{#FF6800}{ 3 } } \color{#FF6800}{ + } \color{#FF6800}{ a } ^ { \color{#FF6800}{ 2 } }$
$\color{#FF6800}{ 6 } \color{#FF6800}{ a } ^ { \color{#FF6800}{ 6 } } \color{#FF6800}{ - } \color{#FF6800}{ 4 } \color{#FF6800}{ a } ^ { \color{#FF6800}{ 5 } } \color{#FF6800}{ + } \color{#FF6800}{ 3 } \color{#FF6800}{ a } ^ { \color{#FF6800}{ 4 } } \color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ a } ^ { \color{#FF6800}{ 3 } } \color{#FF6800}{ + } \color{#FF6800}{ a } ^ { \color{#FF6800}{ 2 } }$
$ $ Bind the expressions with the common factor $ a ^ { 2 }$
$\color{#FF6800}{ a } ^ { \color{#FF6800}{ 2 } } \left ( \color{#FF6800}{ 6 } \color{#FF6800}{ a } ^ { \color{#FF6800}{ 4 } } \color{#FF6800}{ - } \color{#FF6800}{ 4 } \color{#FF6800}{ a } ^ { \color{#FF6800}{ 3 } } \color{#FF6800}{ + } \color{#FF6800}{ 3 } \color{#FF6800}{ a } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ a } \color{#FF6800}{ + } \color{#FF6800}{ 1 } \right )$
Solution search results
search-thumbnail-$4.$ $2$ 
$5$ E What must be added to $3a^{3}-3a^{2}+3a-1$ to get $a^{3}+3a^{2}-3a+1\right)$ 
$6$ 6 What must be subtracted from $a^{4}-1$ $tO$ $O$ get $a^{4}-4a^{3}+6a^{2}-4a+1\right)$ 
$7S$ Subtract $a^{2}-a+1$ from the sum of $-a^{2}+2a+3$ and $3a^{2}-4a+5$
10th-13th grade
Other
search-thumbnail-$5.$ Subtract $a^{4}+5a^{3}-3a^{2}$ from $7a^{5}-2a^{4}-a^{2}+3a$ 
$S0lution:$ 
$\left(7a^{5}-2a^{4}-a^{2}+3a\right)-\left(a^{4}+5a^{3}-3a^{2}\right)$ 
$=7a^{5}-2a^{4}-a^{2}+3a-a^{4}-5a^{3}+3a^{2}$ 
$=7a^{5}+\left(2a^{4}-a^{4}\right)-5a^{3}+\left(a^{2}+3a^{2}\right)+3a$ 
$=7a^{5}-3a^{4}-5a^{3}+2a^{2}+3a$ 
Subtracting vertically yields the same result. 
$7a^{5}$ $2a^{4}$ a? + $3a$ 
at + $5a^{3}$ $3a^{2}$ 
$7a^{5}$ - $3a^{4}$ $5a^{3}$ + $2a^{2}$ + $3a$
7th-9th grade
Other
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