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Formula
Factorize the expression
Answer
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$a ^{ 2 } +7a+6 =$
$\left ( a + 1 \right ) \left ( a + 6 \right )$
Arrange the expression in the form of factorization..
$\color{#FF6800}{ a } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ + } \color{#FF6800}{ 7 } \color{#FF6800}{ a } \color{#FF6800}{ + } \color{#FF6800}{ 6 }$
$ $ Use the factoring formula, $ x^{2} + \left(a+b\right)x + ab = \left(x+a\right)\left(x+b\right)$
$\left ( \color{#FF6800}{ a } \color{#FF6800}{ + } \color{#FF6800}{ 6 } \right ) \left ( \color{#FF6800}{ a } \color{#FF6800}{ + } \color{#FF6800}{ 1 } \right )$
$\left ( \color{#FF6800}{ a } \color{#FF6800}{ + } \color{#FF6800}{ 6 } \right ) \left ( \color{#FF6800}{ a } \color{#FF6800}{ + } \color{#FF6800}{ 1 } \right )$
$ $ Sort the factors $ $
$\left ( \color{#FF6800}{ a } \color{#FF6800}{ + } \color{#FF6800}{ 1 } \right ) \left ( \color{#FF6800}{ a } \color{#FF6800}{ + } \color{#FF6800}{ 6 } \right )$
Solution search results
search-thumbnail-$1.$ Simplify 
$\left(i\right)$ $\dfrac {4x^{2}y} {2z^{2}}\times \dfrac {6xz^{3}} {20y^{4}}$ $.$ $\left(11\right)$ $\dfrac {p^{2}-10p+21} {p-7}$ 
$2.$ Simplify 
$\left(i\right)$ $\dfrac {x+4} {3x+4y}\times \dfrac {9x^{2}-16y^{2}} {2x^{2}+3x-20}$ 
$3.$ Simplify 
$\left(1\right)$ $\dfrac {2a^{2}+5a+3} {3a^{2}+7a+6}\div \dfrac {a^{2}+6a+5} {-5a^{2}-35a-50}$ 
$\left(i^{.i^{.i}}\right)$ $\dfrac {x+2} {4y}\div \dfrac {x^{2}-x-6} {12y^{2}}$ 
$x=a^{2}+3a-4$
10th-13th grade
Other
search-thumbnail-$1.$ Simplify 
$\left(i\right)$ $\dfrac {4x^{2}y} {2z^{2}}\times \dfrac {6xz^{3}} {20y^{4}}$ $.$ $\left(11\right)$ $\dfrac {p^{2}-10p+21} {p-7}$ 
$2.$ Simplify 
$\left(i\right)$ $\dfrac {x+4} {3x+4y}\times \dfrac {9x^{2}-16y^{2}} {2x^{2}+3x-20}$ 
$3.$ Simplify 
$\left(1\right)$ $\dfrac {2a^{2}+5a+3} {3a^{2}+7a+6}\div \dfrac {a^{2}+6a+5} {-5a^{2}-35a-50}$ 
$\left(i^{.i^{.i}}\right)$ $\dfrac {x+2} {4y}\div \dfrac {x^{2}-x-6} {12y^{2}}$ 
$x=a^{2}+3a-4$
10th-13th grade
Other
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