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Solve the equation
Answer
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Graph
$y = 9 x + 1$
$y = 5 x + 3$
$x$Intercept
$\left ( - \dfrac { 1 } { 9 } , 0 \right )$
$y$Intercept
$\left ( 0 , 1 \right )$
$x$Intercept
$\left ( - \dfrac { 3 } { 5 } , 0 \right )$
$y$Intercept
$\left ( 0 , 3 \right )$
$9x+1 = 5x+3$
$x = \dfrac { 1 } { 2 }$
$ $ Solve a solution to $ x$
$9 x + 1 = \color{#FF6800}{ 5 } \color{#FF6800}{ x } + 3$
$ $ Move the variable to the left-hand side and change the symbol $ $
$9 x + 1 \color{#FF6800}{ - } \color{#FF6800}{ 5 } \color{#FF6800}{ x } = 3$
$9 x \color{#FF6800}{ + } \color{#FF6800}{ 1 } - 5 x = 3$
$ $ Move the constant to the right side and change the sign $ $
$9 x - 5 x = 3 \color{#FF6800}{ - } \color{#FF6800}{ 1 }$
$\color{#FF6800}{ 9 } \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 5 } \color{#FF6800}{ x } = 3 - 1$
$ $ Organize the expression $ $
$\color{#FF6800}{ 4 } \color{#FF6800}{ x } = 3 - 1$
$4 x = \color{#FF6800}{ 3 } \color{#FF6800}{ - } \color{#FF6800}{ 1 }$
$ $ Subtract $ 1 $ from $ 3$
$4 x = \color{#FF6800}{ 2 }$
$\color{#FF6800}{ 4 } \color{#FF6800}{ x } = \color{#FF6800}{ 2 }$
$ $ Divide both sides by the same number $ $
$\color{#FF6800}{ x } = \color{#FF6800}{ \dfrac { 1 } { 2 } }$
$ $ 그래프 보기 $ $
Graph
Solution search results
search-thumbnail-What values of $w$ and $x$ make $△BCD=$ $=△$ AEFG? 
$C$ 
$\bar{F} $ 
$w+39$ 
$x+39$ $E$ 
$45$ $49$ 
$B$ $D$ $\vec{G} $ 
$w=$ 
$X=$
10th-13th grade
Geometry
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