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Formula
Solve the equation
Answer
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$9 ^{ 2 } \times 3 ^{ a } = 243 ^{ 3 }$
$a = 11$
Solve the equation
$\color{#FF6800}{ 9 } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ \times } \color{#FF6800}{ 3 } ^ { \color{#FF6800}{ a } } = \color{#FF6800}{ 243 } ^ { \color{#FF6800}{ 3 } }$
$ $ Solve an exponential equation (inequality) by taking the logarithm on both sides $ $
$\log _{ \color{#FF6800}{ 3 } } { \left( \color{#FF6800}{ 9 } ^ { \color{#FF6800}{ 2 } } \right) } \color{#FF6800}{ + } \log _{ \color{#FF6800}{ 3 } } { \left( \color{#FF6800}{ 3 } ^ { \color{#FF6800}{ a } } \right) } = \log _{ \color{#FF6800}{ 3 } } { \left( \color{#FF6800}{ 243 } ^ { \color{#FF6800}{ 3 } } \right) }$
$\log _{ \color{#FF6800}{ 3 } } { \left( \color{#FF6800}{ 9 } ^ { \color{#FF6800}{ 2 } } \right) } \color{#FF6800}{ + } \log _{ \color{#FF6800}{ 3 } } { \left( \color{#FF6800}{ 3 } ^ { \color{#FF6800}{ a } } \right) } = \log _{ \color{#FF6800}{ 3 } } { \left( \color{#FF6800}{ 243 } ^ { \color{#FF6800}{ 3 } } \right) }$
$ $ Solve the equation $ $
$\color{#FF6800}{ a } = \color{#FF6800}{ 11 }$
Solution search results
search-thumbnail-$0y_{3}9^{2}$
7th-9th grade
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search-thumbnail-$32$ $9$ $,9^{2}%$
10th-13th grade
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search-thumbnail-$4^{3}9^{2}$
10th-13th grade
Other
search-thumbnail-$-100p^{3}9^{2}r^{5}$ $\div $ $pr^{3}$
1st-6th grade
Other
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