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Formula
Calculate the value
Answer
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$8a ^{ 2 } b \div 4ab \times ab ^{ 2 }$
$2 a ^ { 2 } b ^ { 2 }$
Arrange the rational expression
$8 a ^ { 2 } \color{#FF6800}{ a } b \div \left ( 4 a b \right ) \times b ^ { 2 }$
$ $ If the exponent is omitted, the exponent of that term is equal to 1 $ $
$8 a ^ { 2 } \color{#FF6800}{ a } ^ { \color{#FF6800}{ 1 } } b \div \left ( 4 a b \right ) \times b ^ { 2 }$
$8 \color{#FF6800}{ a } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ a } ^ { \color{#FF6800}{ 1 } } b \div \left ( 4 a b \right ) \times b ^ { 2 }$
$ $ Add the exponent as the base is the same $ $
$8 \color{#FF6800}{ a } ^ { \color{#FF6800}{ 2 } \color{#FF6800}{ + } \color{#FF6800}{ 1 } } b \div \left ( 4 a b \right ) \times b ^ { 2 }$
$8 a ^ { \color{#FF6800}{ 2 } \color{#FF6800}{ + } \color{#FF6800}{ 1 } } b \div \left ( 4 a b \right ) \times b ^ { 2 }$
$ $ Add $ 2 $ and $ 1$
$8 a ^ { \color{#FF6800}{ 3 } } b \div \left ( 4 a b \right ) \times b ^ { 2 }$
$8 a ^ { 3 } \color{#FF6800}{ b } b ^ { 2 } \div \left ( 4 a b \right )$
$ $ If the exponent is omitted, the exponent of that term is equal to 1 $ $
$8 a ^ { 3 } \color{#FF6800}{ b } ^ { \color{#FF6800}{ 1 } } b ^ { 2 } \div \left ( 4 a b \right )$
$8 a ^ { 3 } \color{#FF6800}{ b } ^ { \color{#FF6800}{ 1 } } \color{#FF6800}{ b } ^ { \color{#FF6800}{ 2 } } \div \left ( 4 a b \right )$
$ $ Add the exponent as the base is the same $ $
$8 a ^ { 3 } \color{#FF6800}{ b } ^ { \color{#FF6800}{ 1 } \color{#FF6800}{ + } \color{#FF6800}{ 2 } } \div \left ( 4 a b \right )$
$8 a ^ { 3 } b ^ { \color{#FF6800}{ 1 } \color{#FF6800}{ + } \color{#FF6800}{ 2 } } \div \left ( 4 a b \right )$
$ $ Add $ 1 $ and $ 2$
$8 a ^ { 3 } b ^ { \color{#FF6800}{ 3 } } \div \left ( 4 a b \right )$
$\color{#FF6800}{ 8 } \color{#FF6800}{ a } ^ { \color{#FF6800}{ 3 } } \color{#FF6800}{ b } ^ { \color{#FF6800}{ 3 } } \color{#FF6800}{ \div } \left ( \color{#FF6800}{ 4 } \color{#FF6800}{ a } \color{#FF6800}{ b } \right )$
$ $ Calculate the multiplication expression $ $
$\color{#FF6800}{ 2 } \color{#FF6800}{ a } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ b } ^ { \color{#FF6800}{ 2 } }$
Solution search results
search-thumbnail-$S$ $1α\times 3$ 
$\dfrac {Q} {T9}^{3}$ $\right)$ $9x=yy$ $+2x\geq +7y$ $\left($ 
$b\right)$ $|a^{2}b$ $-$ $8a^{2}=$ $sab^{2}+3b^{2}+a^{2}23a^{2}b$
7th-9th grade
Other
search-thumbnail-$=xx\times $ $x$ 
$4^{-}$ $8a^{3}+b^{3}+12a^{2}b+6ab^{2}$
10th-13th grade
Other
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