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Formula
Calculate the value
Answer
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$8 \times \dfrac{ 4 }{ 9 }$
$\dfrac { 32 } { 9 }$
Calculate the value
$\color{#FF6800}{ 8 } \times \dfrac { 4 } { 9 }$
$ $ Natural numbers can be expressed as fractions with a denominator of 1 $ $
$\color{#FF6800}{ \dfrac { 8 } { 1 } } \times \dfrac { 4 } { 9 }$
$\color{#FF6800}{ \dfrac { 8 } { 1 } } \color{#FF6800}{ \times } \color{#FF6800}{ \dfrac { 4 } { 9 } }$
$ $ numerator multiply between numerator, and denominators multiply between denominators $ $
$\color{#FF6800}{ \dfrac { 8 \times 4 } { 1 \times 9 } }$
$\dfrac { \color{#FF6800}{ 8 } \color{#FF6800}{ \times } \color{#FF6800}{ 4 } } { 1 \times 9 }$
$ $ Multiply $ 8 $ and $ 4$
$\dfrac { \color{#FF6800}{ 32 } } { 1 \times 9 }$
$\dfrac { 32 } { \color{#FF6800}{ 1 } \times 9 }$
$ $ Multiplying any number by 1 does not change the value $ $
$\dfrac { 32 } { \color{#FF6800}{ 9 } }$
Solution search results
search-thumbnail-$8-x+\dfrac {3} {8}=\dfrac {4} {9}$ 
8.-x+ 
$10$ $\dfrac {3} {2}x+4=\dfrac {1} {3}$
10th-13th grade
Other
search-thumbnail-
$\dfrac {4} {9}8$ 
$\dfrac {5} {3}$ $+$ $\dfrac {5} {9}8+\dfrac {4} {3}\right)$ 
5/3
10th-13th grade
Algebra
search-thumbnail-Which of the following rational numbers are 
equivalent? 
$0Ptionsy$ 
A \frac{5}{6}, \frac{30}{36} 
B $s\sqrt{rac\left(} -2\right)\left(3\right)\sqrt{1rac} \sqrt{4\right)16\right)4} $ 
C $s\sqrt{11aC\left(} -4\right)1-7b,\sqrt{1rac\left(16\sqrt{35\right)9} } $ 
D \frac{1}{2},\frac{3}{8}
7th-9th grade
Other
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