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Solve the equation
Answer
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$y = 7 x - \left ( \left ( x + 5 \right ) - \left ( 3 x - 1 \right ) \right )$
$y = 12$
$x$Intercept
$\left ( \dfrac { 2 } { 3 } , 0 \right )$
$y$Intercept
$\left ( 0 , - 6 \right )$
$7x- [ \left( x+5 \right) - \left( 3x-1 \right) ] = 12$
$x = 2$
$ $ Solve a solution to $ x$
$7 x - \left ( \left ( x + 5 \right ) \color{#FF6800}{ - } \left ( \color{#FF6800}{ 3 } \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 1 } \right ) \right ) = 12$
$ $ Change the symbol of each term in parentheses when there is a (-) symbol in front of parentheses $ $
$7 x - \left ( \left ( x + 5 \right ) \color{#FF6800}{ - } \color{#FF6800}{ 3 } \color{#FF6800}{ x } + \color{#FF6800}{ 1 } \right ) = 12$
$7 x - \left ( \left ( \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 5 } \right ) \color{#FF6800}{ - } \color{#FF6800}{ 3 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 1 } \right ) = 12$
$ $ Get rid of unnecessary parentheses $ $
$7 x - \left ( \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 5 } \color{#FF6800}{ - } \color{#FF6800}{ 3 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 1 } \right ) = 12$
$7 x - \left ( \color{#FF6800}{ x } + 5 \color{#FF6800}{ - } \color{#FF6800}{ 3 } \color{#FF6800}{ x } + 1 \right ) = 12$
$ $ Calculate between similar terms $ $
$7 x - \left ( \color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ x } + 5 + 1 \right ) = 12$
$7 x - \left ( - 2 x + \color{#FF6800}{ 5 } \color{#FF6800}{ + } \color{#FF6800}{ 1 } \right ) = 12$
$ $ Add $ 5 $ and $ 1$
$7 x - \left ( - 2 x + \color{#FF6800}{ 6 } \right ) = 12$
$7 x \color{#FF6800}{ - } \left ( \color{#FF6800}{ - } \color{#FF6800}{ 2 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 6 } \right ) = 12$
$ $ Change the symbol of each term in parentheses when there is a (-) symbol in front of parentheses $ $
$7 x + \color{#FF6800}{ 2 } \color{#FF6800}{ x } \color{#FF6800}{ - } \color{#FF6800}{ 6 } = 12$
$\color{#FF6800}{ 7 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 2 } \color{#FF6800}{ x } - 6 = 12$
$ $ Calculate between similar terms $ $
$\color{#FF6800}{ 9 } \color{#FF6800}{ x } - 6 = 12$
$9 x \color{#FF6800}{ - } \color{#FF6800}{ 6 } = 12$
$ $ Move the constant to the right side and change the sign $ $
$9 x = 12 \color{#FF6800}{ + } \color{#FF6800}{ 6 }$
$9 x = \color{#FF6800}{ 12 } \color{#FF6800}{ + } \color{#FF6800}{ 6 }$
$ $ Add $ 12 $ and $ 6$
$9 x = \color{#FF6800}{ 18 }$
$\color{#FF6800}{ 9 } \color{#FF6800}{ x } = \color{#FF6800}{ 18 }$
$ $ Divide both sides by the same number $ $
$\color{#FF6800}{ x } = \color{#FF6800}{ 2 }$
$ $ 그래프 보기 $ $
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Solution search results
search-thumbnail-If the sum of two consecutive 
numbers is $45$ and one number is $X$ 
.This statement in the form of 
equation $1s:$ 
$\left(1$ Point) $\right)$ 
$○5x+1$ $1eft\left(x+1$ $r1gnt\right)=45s$ 
$○sx+1ef\left(x+2$ $r1gnt\right)=145s$ 
$sx+1x=45s$
7th-9th grade
Algebra
search-thumbnail-$s|ef\left(-1n$ $\left($ }\right)^{50}\ $\right)$ \ | | is\ equal\ to\ $S$ 
$s1S$ 
$S-1S$ 
$s2S$ 
$s50s$
7th-9th grade
Other
search-thumbnail-Given the set of ordered pairs $\left(\left(-7.0\right),\left(-6,5\right),\left(-5,-3\right),\left(-1,2\right)$ $\left(1,6\right),\left(2,-2\right)$ $\left(5,3\right)\left(7,-8\right)\right)$ 
Find f(7)fAleft(7\right) 
O a 
O b -8 
6. 
$5$
7th-9th grade
Algebra
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