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Formula
Solve the equation
Answer
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Graph
$y = 7 + x - 5$
$y = 7 + 3$
$x$Intercept
$\left ( - 2 , 0 \right )$
$y$Intercept
$\left ( 0 , 2 \right )$
$7+x-5 = 7+3$
$x = 8$
$ $ Solve a solution to $ x$
$\color{#FF6800}{ 7 } + x \color{#FF6800}{ - } \color{#FF6800}{ 5 } = 7 + 3$
$ $ Subtract $ 5 $ from $ 7$
$\color{#FF6800}{ 2 } + x = 7 + 3$
$2 + x = \color{#FF6800}{ 7 } \color{#FF6800}{ + } \color{#FF6800}{ 3 }$
$ $ Add $ 7 $ and $ 3$
$2 + x = \color{#FF6800}{ 10 }$
$\color{#FF6800}{ 2 } \color{#FF6800}{ + } \color{#FF6800}{ x } = 10$
$ $ Organize the expression $ $
$\color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 2 } = 10$
$x \color{#FF6800}{ + } \color{#FF6800}{ 2 } = 10$
$ $ Move the constant to the right side and change the sign $ $
$x = 10 \color{#FF6800}{ - } \color{#FF6800}{ 2 }$
$x = \color{#FF6800}{ 10 } \color{#FF6800}{ - } \color{#FF6800}{ 2 }$
$ $ Subtract $ 2 $ from $ 10$
$x = \color{#FF6800}{ 8 }$
$ $ 그래프 보기 $ $
Graph
Solution search results
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$7+$ $+3$ 37 $+5+-$ $5$ $=$ 
$+$ $-$ $5+$ $+3$ $+\dfrac {c} {5}$ $=$ 
6 $+$ + 3 + $9-+37$ $+$ $+3$ 37T $=$ 
I + 37 + $+37$ $+$ $+37$ $=$ 
$12$
7th-9th grade
Other
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$-$ $α+3=$ 
$7\div 3=$ 
$α99+1=$
10th-13th grade
Other
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$2x+2$ $22x^{2}+32\pi ^{++}$
1st-6th grade
Algebra
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