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Formula
Factorize the expression
Answer
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$6x ^{ 2 } +19xy+10y ^{ 2 }$
$\left ( 2 x + 5 y \right ) \left ( 3 x + 2 y \right )$
Arrange the expression in the form of factorization..
$\color{#FF6800}{ 6 } \color{#FF6800}{ x } ^ { \color{#FF6800}{ 2 } } \color{#FF6800}{ + } \color{#FF6800}{ 19 } \color{#FF6800}{ x } \color{#FF6800}{ y } \color{#FF6800}{ + } \color{#FF6800}{ 10 } \color{#FF6800}{ y } ^ { \color{#FF6800}{ 2 } }$
$ $ Do factorization $ $
$\left ( \color{#FF6800}{ 2 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 5 } \color{#FF6800}{ y } \right ) \left ( \color{#FF6800}{ 3 } \color{#FF6800}{ x } \color{#FF6800}{ + } \color{#FF6800}{ 2 } \color{#FF6800}{ y } \right )$
Solution search results
search-thumbnail-$a41<$ 
व्यंजक $6x^{2}+9xy+10y^{2}$ और $p^{2}+pq-q^{2}$ के पदों में संख्यात 
अभ्यास 6 (a) 
नलिखित व्यंजकों के पदों को लिखिए : 
$5x+6$ $2.$ $a^{2}-3ab-4$ 3. $4ax+6$ 
$x^{2}-3x-7$ 5. $5a-b$ $6$ $xy^{2}$ 
$xyz$ में $xyz$ का गुणांक... है $8.$ $-3y^{2}$ में $y^{2}$ का गु 
$-2$ $-2$
10th-13th grade
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