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Formula
Calculate the value
Answer
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$6.02 \times 10 ^{ 23 }$
$301 \times 2 ^ { 22 } \times 5 ^ { 21 }$
Calculate the value
$\color{#FF6800}{ 6.02 } \times 10 ^ { 23 }$
$ $ Convert decimals to fractions $ $
$\color{#FF6800}{ \dfrac { 301 } { 50 } } \times 10 ^ { 23 }$
$\color{#FF6800}{ \dfrac { 301 } { 50 } } \color{#FF6800}{ \times } \color{#FF6800}{ 10 } ^ { \color{#FF6800}{ 23 } }$
$ $ Arrange the terms multiplied by fractions $ $
$\color{#FF6800}{ \dfrac { 301 \times 10 ^ { 23 } } { 50 } }$
$\color{#FF6800}{ \dfrac { 301 \times 10 ^ { 23 } } { 50 } }$
$ $ Calculate the fraction $ $
$\color{#FF6800}{ \dfrac { 2 ^ { 23 } \times 5 ^ { 23 } \times 7 \times 43 } { 50 } }$
$\color{#FF6800}{ \dfrac { 2 ^ { 23 } \times 5 ^ { 23 } \times 7 \times 43 } { 50 } }$
$ $ Reduce the fraction $ $
$\color{#FF6800}{ 2 } ^ { \color{#FF6800}{ 22 } } \color{#FF6800}{ \times } \color{#FF6800}{ 5 } ^ { \color{#FF6800}{ 21 } } \color{#FF6800}{ \times } \color{#FF6800}{ 7 } \color{#FF6800}{ \times } \color{#FF6800}{ 43 }$
$\color{#FF6800}{ 2 } ^ { \color{#FF6800}{ 22 } } \color{#FF6800}{ \times } \color{#FF6800}{ 5 } ^ { \color{#FF6800}{ 21 } } \color{#FF6800}{ \times } \color{#FF6800}{ 7 } \color{#FF6800}{ \times } \color{#FF6800}{ 43 }$
$ $ Simplify the expression $ $
$\color{#FF6800}{ 301 } \color{#FF6800}{ \times } \color{#FF6800}{ 2 } ^ { \color{#FF6800}{ 22 } } \color{#FF6800}{ \times } \color{#FF6800}{ 5 } ^ { \color{#FF6800}{ 21 } }$
Solution search results
search-thumbnail-of $25.$ Number of oxygen atoms in $89$ of $o2OnQ$ $1s-$ 
$\left(1\right)6.02\times 1023$ $\left(2\right)$ $6.02\times 10^{23}$ 
$2$ 
$\left(3\right)$ $\dfrac {6.02\times 10^{23}} {3}$ $\left(4\right)$ $6.02\times 10^{23}$ 
$6$
10th-13th grade
Chemistry
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