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Answer
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$6 \times \left( - \dfrac{ 3 }{ 4 } \right)$
$- \dfrac { 9 } { 2 }$
Calculate the value
$6 \times \left ( \color{#FF6800}{ - } \dfrac { 3 } { 4 } \right )$
$ $ If you multiply negative numbers by odd numbers, move the (-) sign forward $ $
$\color{#FF6800}{ - } \left ( 6 \times \dfrac { 3 } { 4 } \right )$
$- \left ( \color{#FF6800}{ 6 } \times \dfrac { 3 } { 4 } \right )$
$ $ Natural numbers can be expressed as fractions with a denominator of 1 $ $
$- \left ( \color{#FF6800}{ \dfrac { 6 } { 1 } } \times \dfrac { 3 } { 4 } \right )$
$- \left ( \dfrac { \color{#FF6800}{ 6 } } { 1 } \times \dfrac { 3 } { \color{#FF6800}{ 4 } } \right )$
$ $ Reduce all denominators and numerators that can be reduced $ $
$- \left ( \dfrac { \color{#FF6800}{ 3 } } { 1 } \times \dfrac { 3 } { \color{#FF6800}{ 2 } } \right )$
$- \left ( \color{#FF6800}{ \dfrac { 3 } { 1 } } \color{#FF6800}{ \times } \color{#FF6800}{ \dfrac { 3 } { 2 } } \right )$
$ $ numerator multiply between numerator, and denominators multiply between denominators $ $
$- \color{#FF6800}{ \dfrac { 3 \times 3 } { 1 \times 2 } }$
$- \dfrac { \color{#FF6800}{ 3 } \color{#FF6800}{ \times } \color{#FF6800}{ 3 } } { 1 \times 2 }$
$ $ Multiply $ 3 $ and $ 3$
$- \dfrac { \color{#FF6800}{ 9 } } { 1 \times 2 }$
$- \dfrac { 9 } { \color{#FF6800}{ 1 } \times 2 }$
$ $ Multiplying any number by 1 does not change the value $ $
$- \dfrac { 9 } { \color{#FF6800}{ 2 } }$
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