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Formula
Calculate the value
Answer
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$6 \times \dfrac{ 7 }{ 8 }$
$\dfrac { 21 } { 4 }$
Calculate the value
$\color{#FF6800}{ 6 } \times \dfrac { 7 } { 8 }$
$ $ Natural numbers can be expressed as fractions with a denominator of 1 $ $
$\color{#FF6800}{ \dfrac { 6 } { 1 } } \times \dfrac { 7 } { 8 }$
$\dfrac { \color{#FF6800}{ 6 } } { 1 } \times \dfrac { 7 } { \color{#FF6800}{ 8 } }$
$ $ Reduce all denominators and numerators that can be reduced $ $
$\dfrac { \color{#FF6800}{ 3 } } { 1 } \times \dfrac { 7 } { \color{#FF6800}{ 4 } }$
$\color{#FF6800}{ \dfrac { 3 } { 1 } } \color{#FF6800}{ \times } \color{#FF6800}{ \dfrac { 7 } { 4 } }$
$ $ numerator multiply between numerator, and denominators multiply between denominators $ $
$\color{#FF6800}{ \dfrac { 3 \times 7 } { 1 \times 4 } }$
$\dfrac { \color{#FF6800}{ 3 } \color{#FF6800}{ \times } \color{#FF6800}{ 7 } } { 1 \times 4 }$
$ $ Multiply $ 3 $ and $ 7$
$\dfrac { \color{#FF6800}{ 21 } } { 1 \times 4 }$
$\dfrac { 21 } { \color{#FF6800}{ 1 } \times 4 }$
$ $ Multiplying any number by 1 does not change the value $ $
$\dfrac { 21 } { \color{#FF6800}{ 4 } }$
Solution search results
search-thumbnail-Can you answer this? 
$20$ $25$ 

$18$ 

$\left($ 
$\left(A\right)$ $A\right)2$ 
$21frac\left(5\right)\left(9\right)$ \) 
$\left(B\right)$ $B\right)$ $1\left(211$ 
$\left(C\right)$ $1\left(21$ $21+rac\left(7\right)+9\right)$ \) 
$\left(D\right)$ $1\left(2\right)$ 2\frac{8}{9} 
$ac\left(8\right)\left(9\right)$ \) $9:18PM\sqrt{} $
1st-6th grade
Algebra
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